CHEM 120 (chem120)

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Here are the best resources to pass CHEM 120 (chem120). Find CHEM 120 (chem120) study guides, notes, assignments, and much more.

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CHEM 120| Week 1 Discussion Question 1| Scientific Method and Calculations
  • CHEM 120| Week 1 Discussion Question 1| Scientific Method and Calculations

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CHEM 120| Unit 3 Discussion 2| Molarity and Solution Calculations
  • CHEM 120| Unit 3 Discussion 2| Molarity and Solution Calculations

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CHEM 120| Final Exam| Practice Q&A| Graded A+
  • CHEM 120| Final Exam| Practice Q&A| Graded A+

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  • CHEM 120 FINAL EXAM PRACTICE QUESTIONS & ANSWERS
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CHEM 120| Midterm Study Guide
  • CHEM 120| Midterm Study Guide

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CHEM 120| WEEK 6| DISCUSSION 1-POLYMERS| (GRADED A)
  • CHEM 120| WEEK 6| DISCUSSION 1-POLYMERS| (GRADED A)

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CHEM 120| Final Exam Study Guide||
  • CHEM 120| Final Exam Study Guide||

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  CHEM 120| Week 4 DQ| ACIDS & BASES
  • CHEM 120| Week 4 DQ| ACIDS & BASES

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CHEM 120| Week 2 Discussion 1| Chemical Names
  • CHEM 120| Week 2 Discussion 1| Chemical Names

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CHEM 120 Week 8 Final Exam COMPLETE (100% CORRECT SOLUTIONS) | Already GRADED A.
  • CHEM 120 Week 8 Final Exam COMPLETE (100% CORRECT SOLUTIONS) | Already GRADED A.

  • Exam (elaborations) • 22 pages • 2021
  • 6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, ( V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 +273) Thus, T1 = 95 + 273 = 368. We have V1 (165 mL) & T2 = (25 + 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 0 7 Short 16 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant tempera...
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