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ALEV CHEM BORN-HABER CYCLE UPDATED Actual Questions and CORRECT Answers

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ALEV CHEM BORN-HABER CYCLE UPDATED Actual Questions and CORRECT Answers Define the term electron affinity for chlorine - CORRECT ANSWER- The enthalpy change / heat energy change / ΔH for the formation of one mole of (chloride) ions from (chlorine) atoms A 5.00 g sample of potassium chlorid...

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  • October 6, 2024
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  • 2024/2025
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  • ALEV CHEM BORN-HABER CYCLE
  • ALEV CHEM BORN-HABER CYCLE
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MGRADES
ALEV CHEM BORN-HABER CYCLE
UPDATED Actual Questions and
CORRECT Answers
Define the term electron affinity for chlorine - CORRECT ANSWER✔✔- The enthalpy
change / heat energy change / ΔH for the formation of one mole of (chloride)
ions from (chlorine) atoms


A 5.00 g sample of potassium chloride was added to 50.0 g of water initially at 20.0 °C. The
mixture was stirred and as the potassium chloride dissolved, the temperature of the

solution decreased. - CORRECT ANSWER✔✔- Start a clock when KCl is added to water
Record the temperature every subsequent minute for about 5 minutes
Allow record the temperature at regular time intervals
untilsome time after all the solid has dissolved for M2
Plot a graph of temperature vs time
Extrapolate back to time of mixing = 0 and determine the temperature


The temperature of the water decreased to 14.6 °C.
Calculate a value, in kJ mol−1, for the enthalpy of solution of potassium chloride.
You should assume that only the 50.0 g of water changes in temperature and that
the specific heat capacity of water is 4.18 J K−1 g−1
.
Give your answer to the appropriate number of significant figures. - CORRECT
ANSWER✔✔- Heat taken in = m × c × ΔT = 50 × 4.18 × 5.4 = 1128.6 J
Moles of KCl = 5..6 = 0.0670
Enthalpy change per mole = +1128..0670 = 16 839 J mol-1
= +16.8 (kJ mol-1)
Answer must be given to this precision


The enthalpy of solution of calcium chloride is −82.9 kJ mol−1
.

, The enthalpies of hydration for calcium ions and chloride ions are −1650 and
−364 kJ mol−1, respectively.
Use these values to calculate a value for the lattice enthalpy of dissociation of

calcium chloride. - CORRECT ANSWER✔✔- ΔHsolution = ΔHlattice + ΔH(hydration of
calcium ions) + 2 × ΔH(hydration of chloride
ions)
ΔHlattice = ΔHsolution - ΔH(hydration of calcium ions) -2 ×ΔH(hydration of chloride
ions)/
ΔHlattice = -82-9 - (-1650 + 2 × -364) = +2295 (kJ mol-1)


Explain why the lattice enthalpy of calcium chloride is different from the lattice enthalpy of

dissociation for magnesium chloride. - CORRECT ANSWER✔✔- Magnesium ion is smaller
than the calcium ion
1
Therefore, it attracts the chloride ion more strongly / stronger ionic bonding


Write an equation for the process that has an enthalpy change equal to the electron affinity of
chlorine - CORRECT ANSWER✔✔- Cl(g) + e → Cl(g)
State symbols essential
Allow e with no charge
This and all subsequent equations must be balanced


In terms of electrostatic forces, suggest why the electron affinity of fluorine has a negative
value. - CORRECT ANSWER✔✔- There is an attraction between the nucleus / protons and
(the added)
electron(s)


A theoretical value for enthalpy of lattice dissociation can be calculated using a
perfect ionic model.
The theoretical enthalpy of lattice dissociation for silver fluoride is +870 kJ mol-1
.
(i) Explain why the theoretical enthalpy of lattice dissociation for silver fluoride is

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