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MATH 110 Module 4 Exam.| PORTGE LEARNING
MATH 110 Module 4 Exam.| PORTGE LEARNING 
Module 4 Exam 
Exam Page 1 
A factory has eight safety systems. During an emergency, the probability of any one of the safety systems failing is .08. What is the probability that six or more safety systems will fail during an emergency? 
 
f(x) = ( (n!) / (x!(n-x)!) ) x ( (p^x) x ((1-p)^n-x)) ) n = 8 
x = 6, 7, 8 (number of failures) 
p = 0.08 
 
 
6	failures: 
n = 8 
x = 6 
p = 0.8 
n-x = 8-6 = 2 
( (8!) / (6!(2)!) ) x ( (0.08^6) x ((1-0.08)^2)) ) = 6.2...
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MATH 110 Module 4 Exam.| PORTGE LEARNING 
Module 4 Exam 
Exam Page 1 
A factory has eight safety systems. During an emergency, the probability of any one of the safety systems failing is .08. What is the probability that six or more safety systems will fail during an emergency? 
 
f(x) = ( (n!) / (x!(n-x)!) ) x ( (p^x) x ((1-p)^n-x)) ) n = 8 
x = 6, 7, 8 (number of failures) 
p = 0.08 
 
 
6	failures: 
n = 8 
x = 6 
p = 0.8 
n-x = 8-6 = 2 
( (8!) / (6!(2)!) ) x ( (0.08^6) x ((1-0.08)^2)) ) = 6.2...
MATH 110 – Module 1 (Book Exam) Limespring.com Questions 1-18
MATH 110 – Module 1 (Book Exam) L Questions 1-18
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MATH 110 – Module 1 (Book Exam) L Questions 1-18
	MATH 110 Module 1 Exam.| PORTGE LEARNING
MATH 110 Module 1 Exam.| PORTGE LEARNING 
Module 1 Exam 
 
 
 
 
2. Explain statistical inference.
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MATH 110 Module 1 Exam.| PORTGE LEARNING 
Module 1 Exam 
 
 
 
 
2. Explain statistical inference.
MATH 110 MODULE 3 EXAM
MATH 110 MODULE 3 EXAM 
 
Module 3 Exam 
Exam Page 1 
Suppose A and B are two events with probabilities: 
 
P(Ac )=.40,P(B)=.45,P(A∪B)=.60. 
 
 
Find the following: 
a)	P(A∩B). 
 
p(anb) = p(a) + p(b) - p(aub) p(a) = 1 - p(a^c) 
p(a^c) = 0.40 
1 - 0.40 = 0.60 
p(a) = 0.60 
 
 
0.60 + 0.45 - 0.60 = 0.45 
 
 
P(AnB) = 0.45 
 
b)	P(A). 
 
p(a) = 1 - p(a^c) p(a^c) = 0.40 
 
1 - 0.40 = 0.60 
 
 
P(A) = 0.60 
 
c)	P(Bc). 
 
p(b) = 1 - p(b^c) 
rearranged to find p(b^c) = 1 - p(b) 
 
 
1 - 0.45 = 0....
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MATH 110 MODULE 3 EXAM 
 
Module 3 Exam 
Exam Page 1 
Suppose A and B are two events with probabilities: 
 
P(Ac )=.40,P(B)=.45,P(A∪B)=.60. 
 
 
Find the following: 
a)	P(A∩B). 
 
p(anb) = p(a) + p(b) - p(aub) p(a) = 1 - p(a^c) 
p(a^c) = 0.40 
1 - 0.40 = 0.60 
p(a) = 0.60 
 
 
0.60 + 0.45 - 0.60 = 0.45 
 
 
P(AnB) = 0.45 
 
b)	P(A). 
 
p(a) = 1 - p(a^c) p(a^c) = 0.40 
 
1 - 0.40 = 0.60 
 
 
P(A) = 0.60 
 
c)	P(Bc). 
 
p(b) = 1 - p(b^c) 
rearranged to find p(b^c) = 1 - p(b) 
 
 
1 - 0.45 = 0....
MATH 110 TEST 3- PORTAGE LEARNING
MATH 110 TEST 3- PORTAGE LEARNING
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- • 4 pages •
MATH 110 TEST 3- PORTAGE LEARNING
CHAPTER 3 MATH 110| PORTAGE LEARNING
CHAPTER 3 MATH 110| PORTAGE LEARNING 
 
 
Chapter 3 math 110
- Exam (elaborations)
- • 8 pages •
CHAPTER 3 MATH 110| PORTAGE LEARNING 
 
 
Chapter 3 math 110
MATH 110 MODULE 7 EXAM. | PORTAGE LEARNING
MATH 110 MODULE 7 EXAM. | PORTAGE LEARNING 
 
Module 7 Exam
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MATH 110 MODULE 7 EXAM. | PORTAGE LEARNING 
 
Module 7 Exam
MATH 110 Module 2 Exam.| PORTGE LEARNING
MATH 110 Module 2 Exam.| PORTGE LEARNING 
 
Module 2 Exam 
 
Exam Page 1 
During an hour at a fast food restaurant, the following types of sandwiches are ordered: 
 
Cheeseburger	Fish	Cheeseburger	Hamburger	Fish		Chicken Hamburger	Cheeseburger		Fish Hamburger		Turkey	Fish	Chicken Chicken	Fish		Turkey	Fish	Hamburger	Fish 
Cheeseburger	Fish		Cheeseburger	Hamburger	Fish	Fish Cheeseburger	Hamburger	Fish		Turkey	Turkey		Chicken	Fish Chicken		Cheeseburger	Fish	Turkey	Fish	Fish		Hamburger Fish	Fish	Tur...
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MATH 110 Module 2 Exam.| PORTGE LEARNING 
 
Module 2 Exam 
 
Exam Page 1 
During an hour at a fast food restaurant, the following types of sandwiches are ordered: 
 
Cheeseburger	Fish	Cheeseburger	Hamburger	Fish		Chicken Hamburger	Cheeseburger		Fish Hamburger		Turkey	Fish	Chicken Chicken	Fish		Turkey	Fish	Hamburger	Fish 
Cheeseburger	Fish		Cheeseburger	Hamburger	Fish	Fish Cheeseburger	Hamburger	Fish		Turkey	Turkey		Chicken	Fish Chicken		Cheeseburger	Fish	Turkey	Fish	Fish		Hamburger Fish	Fish	Tur...
MATH 110 MODULE 6 EXAM.| PORTAGE LEARNING
MATH 110 MODULE 6 EXAM.| PORTAGE LEARNING 
 
Module 6 Exam 
 
 
 
 
 
 
 
 
 
 
 
 
2610 - 1.28(560 / √40) √[(415-40)/(415-1)] < u < 2610 + 1.28(560 / √40) √[(415-40)/(415-1)] 
= 2502.13, 2717.87 
 
2502.13 < u < 2717.87
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MATH 110 MODULE 6 EXAM.| PORTAGE LEARNING 
 
Module 6 Exam 
 
 
 
 
 
 
 
 
 
 
 
 
2610 - 1.28(560 / √40) √[(415-40)/(415-1)] < u < 2610 + 1.28(560 / √40) √[(415-40)/(415-1)] 
= 2502.13, 2717.87 
 
2502.13 < u < 2717.87
NRSE 4560 Gerontology Student Handbook
NRSE 4560 Gerontology Student Handbook 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
- 1 - 
 
GeroV.1 
 
 
 
 
Gerontology Handbook 
 
Table of Contents 
Focused Exam: Pain	. - 3 - 
Focused Exam: Mobility ................................................................................................................. - 6 - 
Focused Exam: Infection ............................................................................................................... - 9 - 
Focus...
- Exam (elaborations)
- • 27 pages •
NRSE 4560 Gerontology Student Handbook 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
- 1 - 
 
GeroV.1 
 
 
 
 
Gerontology Handbook 
 
Table of Contents 
Focused Exam: Pain	. - 3 - 
Focused Exam: Mobility ................................................................................................................. - 6 - 
Focused Exam: Infection ............................................................................................................... - 9 - 
Focus...