What is the mk 105 - Study guides, Class notes & Summaries

1. Proteins necessary for body's mainte- nance, growth, and repair (GS) 2. Carbohydrates and Fats used primarily for energy (GS) 3. 212 Water boils at degrees fahrenheit (GS) 4. 100 Water boils at degrees Cel- sius (GS) 5. 373 Water boils at Ks on the Kelvin scale (GS) 6. Veins carry blood from capillaries toward the heart. (GS) 7. Arteries carry blood away from the heart. (GS) 8. Ventricles lower chamber of the heart (GS) 9. Red Blood Cells component of blood which car- ri...

Ammo Qual/Cert Questions And Answers 2024 OP-4 - Correct Answer-Ammunition Afloat OP-5 VOL 1 - Correct Answer-Ammunition and Explosives Ashore OP-2173 VOL 1 AND 2 - Correct Answer-Ammunition Handling Equipment for Weapons OP-3347 - Correct Answer-Ordnance Safety Precautions SW023-AH-WHM-010 - Correct Answer-Handling Of Ammo & Explosives with (MHE) 11-1F-2 - Correct Answer-Bomb & Rocket Fuze Manual 11-5A-2 - Correct Answer-A/C General Purpose Bombs 01-1A-75 - Correct Answer-...

AWS-AMCM EXAM!!

Qual/ Cert, QUAL CERT, Ammo qual/cert Questions and Answers 2023 OP-4 Ammunition Afloat OP-5 VOL 1 Ammunition and Explosives Ashore OP-2173 VOL 1 AND 2 Ammunition Handling Equipment for Weapons OP-3347 Ordnance Safety Precautions SW023-AH-WHM-010 Handling Of Ammo & Explosives with (MHE) 11-1F-2 Bomb & Rocket Fuze Manual 11-5A-2 A/C General Purpose Bombs 01-1A-75 Corrosion Control of Airborne Weapons 01-700 Used to verify that the ...

15 kg/s of air are compressed from 1 atm and 300K (enthalpy of 300.19 kJ/kg) to 2 atm and 900K (enthalpy of 732.93 kJ/kg). Heat transfer is negligible. The air compressor's power output is most nearly (A) 5.6 MW (B) 6.5 MW (C) 7.6 MW (D) 8.9 MW - answer-B What is most nearly the weight in lbf if a 1.00lbm object in a gravitational field of 27.5ft/s^2? (A) 0.85lbf (B) 1.2lbf (C) 28lbf (D) 32lbf - answer-A A rocket that has a mass of 4000 lbm travels at 27,000 ft/sec. What is mo...

WHICH OF THE FOLLOWING IS NOT AN EXAMPLE OF SHIPBOARD ORDNANCE HANDLING EQUIPMENT? - Answer- CRANES IF A MAGAZINE TEMPERATURE HAS EXCEEDED THE REQUIRED STOWAGE TEMPERATURE, THE MAGAZINE MUST BE ARTIFICIALLY COOLED AS PRACTICAL, AND AN ENTRY MADE IN - Answer- RED IN THE WEAPONS DEPARTMENT LOG WHAT IS THE METHOD FOR REPORTING TRANSACTIONS INVOLVING NAVAL CONVETIONAL ORDANANCE TRANSMITTED VIA FORMATTED MESSAGE FOR ALL TRANSACTION TYPES? - Answer- AMMUNITION TRANSACTION REPORTS METHOD THE P...

1. Convert the following to engineering notation: (a) 0.045 W  45103 W = 45 mW (b) 2000 pJ  2000 1012  2 109 J = 2 nJ (c) 0.1 ns  0.1109  100 1012 s = 100 ps (d) 39,212 as = 3.9212×104×10-18 = 39.212×10-15 s = (f) 18,000 m  18 103m= 18 km (g) 2,500,000,000,000 bits  2.51012 bits = 2.5 terabits 1015 atoms  102 cm  3 (h)    1021 atoms/m3 (it’s unclear what a “zeta atom” is)  cm3  1 m...

1. Convert the following to engineering notation: (a) 0.045 W  45103 W = 45 mW (b) 2000 pJ  2000 1012  2 109 J = 2 nJ (c) 0.1 ns  0.1109  100 1012 s = 100 ps (d) 39,212 as = 3.9212×104×10-18 = 39.212×10-15 s = (f) 18,000 m  18 103m= 18 km (g) 2,500,000,000,000 bits  2.51012 bits = 2.5 terabits 1015 atoms  102 cm  3 (h)    1021 atoms/m3 (it’s unclear what a “zeta atom” is)  cm3  1 m...

1. Convert the following to engineering notation: (a) 0.045 W  45103 W = 45 mW (b) 2000 pJ  2000 1012  2 109 J = 2 nJ (c) 0.1 ns  0.1109  100 1012 s = 100 ps (d) 39,212 as = 3.9212×104×10-18 = 39.212×10-15 s = (f) 18,000 m  18 103m= 18 km (g) 2,500,000,000,000 bits  2.51012 bits = 2.5 terabits 1015 atoms  102 cm  3 (h)    1021 atoms/m3 (it’s unclear what a “zeta atom” is)  cm3  1 m...

1. Convert the following to engineering notation: (a) 0.045 W  45103 W = 45 mW (b) 2000 pJ  2000 1012  2 109 J = 2 nJ (c) 0.1 ns  0.1109  100 1012 s = 100 ps (d) 39,212 as = 3.9212×104×10-18 = 39.212×10-15 s = (f) 18,000 m  18 103m= 18 km (g) 2,500,000,000,000 bits  2.51012 bits = 2.5 terabits 1015 atoms  102 cm  3 (h)    1021 atoms/m3 (it’s unclear what a “zeta atom” is)  cm3  1 m...