Chem120 week 5 exam - Study guides, Class notes & Summaries

CHEM120 Week 8: Exam 3 (Units 5, 6, and 7) – With 100% Correct Answers- Download To Score An A+ 1. Question: (TCO 7) (a, 5 pts) Given that the molar mass of H3PO4 is 97.994 grams, determine t he number of grams of H3PO4 needed to prepare 0.25L of a 0.2M H3PO4 solution. Show your work. (b, 5 pts) What volume, in Liters, of a 0.2 M H3PO4 solution can be prepared by diluting 50 mL of a 5M H3PO4 solution? Show your work. (Pts. : 10) A. Molarity = moles of solute/liters of solution moles of solute ...

1. A solution is prepared by dissolving 50 g of KCl (74.6 g/mol) to a volume of 1 L. What is the molarity of this solution? 2. You prepare a solution by dissolving 20 g of NaCl to a volume of 350 mL in water. What is the mass/volume % concentration of this solution? 3. When the following reaction goes in the forward direction, what is the base? 4. You are preparing a buffered solution. So far, your solution contains H2PO4- ions, what would you add to this solution to prepare your buffer sy...

CHEM 120 Week 5 Exam 2 (Units 3 and 4)

CHEM 120 Week 8 Exam 3 (Units 5, 6, and 7)

Week 8 : Final Exam Questions - Final Exam CHEM120 Final-Exam- 1. Question: (TCO 7) (a, 5 pts) Given that the molar mass of H3PO4 is 97.994 grams, determine the number of grams of H3PO4 needed to prepare 0.25L of a 0.2M H3PO4 solution. Show your work. (b, 5 pts) What volume, in Liters, of a 0.2 M H3PO4 solution can be prepared by diluting 50 mL of a 5M H3PO4 solution? Show your work. (Pts. : 10) A. Molarity = moles of solute/liters of solution moles of solute = 0.2 M*0.25 L = 0.05 m...

CHEM120 Students: The first exam in your science course is approaching. The General Education Academic Support is here to help. What can you do ahead of Exam 1? 1. Attend a live exam review Thursday, May 12th 6 PM MT Exam 1 Review Join Meeting here: Click here to join 2. Watch the recording of an exam review Click here to watch recorded exam review 3. Schedule a 1:1 appointment with a tutor Click here to book 4. Review the topic videos from weeks 1 and 2 Click her to review ...

CHEM120 Students: The first exam in your science course is approaching. The General Education Academic Support is here to help. What can you do ahead of Exam 1? 1. Attend a live exam review Thursday, May 12th 6 PM MT Exam 1 Review Join Meeting here: Click here to join 2. Watch the recording of an exam review Click here to watch recorded exam review 3. Schedule a 1:1 appointment with a tutor Click here to book 4. Review the topic videos from weeks 1 and 2 Click her to review ...

6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, ( V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 +273) Thus, T1 = 95 + 273 = 368. We have V1 (165 mL) & T2 = (25 + 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 0 7 Short 16 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant tempera...

6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, ( V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 +273) Thus, T1 = 95 + 273 = 368. We have V1 (165 mL) & T2 = (25 + 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 0 7 Short 16 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant tempera...

CHEM120 FINAL EXAM -WEEK 8- PAGE 3- 100% Question: (TCO 7) (a, 5 pts) Given that the molar mass of H3PO4 is 97.994 grams, determine the number of grams of H3PO4 needed to prepare 0.25L of a 0.2M H3PO4 solution. Show your work. (b, 5 pts) What volume, in Liters, of a 0.2 M H3PO4 solution can be prepared by diluting 50 mL of a 5M H3PO4 solution? Show your work. Question: (TCO 7) (a, 5 pts) What is the mass/volume percent of a solution prepared by dissolving 43 g of NaOH in enough water to make ...