Chem 1332 - Study guides, Class notes & Summaries
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CHEM 1332 Practice Exam 1 Questions & Answers Solved 100% Correct!!
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What molality of pentane solution is obtained by dissolving 5.0 g pentane, C5H12, in 245.0 g hexane, 
C6H14? Enter your answer with two decimal places and no units. 
Molar mass pentane: 72.15 g/mol 
Molar mass hexane: 86.18 g/mol - 0.28 
5 g pentane x (1 mol/ 72 g)= 0.069 mol pentane 
245g > .245 kg hexane 
0.069 mol/ .245= 0.28 
If an aqueous CsCl solution is 7.28% CsCl (by mass) and has a density of 1.05 g/mL at 20.°C,what is the 
expected boiling point of the solution? Kb = 0.51°C/m for ...
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CHEM 1332 Final Questions With 100% Correct!!
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Molarity (M) - mols solute / L of solution 
Molality (m) - mols solute / kg solvent 
Freezing point depression / boiling point elevation 
deltaT(b) or deltaT(f) - deltaT(b or f) = i*K(b or f)*m 
i = Van't Hoff factor 
Kb or Kf = constant 
m = molality of solute 
Osmotic pressure (pi) - pi = i*M*R*T 
i = Van't Hoff factor 
M = molarity 
R = gas law constant 0.08206 L*atm/K*mol 
T = temperature (K) 
Van't Hoff factor (i) - i = mols of particles in solution / mols of solute dissolves 
applies fo...
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