Chem 121 - Study guides, Class notes & Summaries

CHEM 121 FINAL EXAM 2024 Updated Questions and Answers Updated (2024 / 2025) (Verified Answers)- PORTAGE LEARNING

Show the determination of the charge on the ion formed by the Mg12 atom. Mg has a +2 charge S 2S 2P 3S also you can just look at the periodic table and see that it is in collumn 2 on the left side and would know that it has a +2 charge because the 2 columns on the left are + this is day 1 chem 101 knowledge 12 2 2 6 2 Mg (metal = lose electrons) 1s 2s 2p 3s lose 2e → Mg 12 2 2 6 2 +2 Ques 10 / 10 pts tion 2

CHEM 121 Final Exam Questions and Answers – Portage Learning. Do the three conversions shown below, showing all work: 1. 328 K = ? oC 2. 76oC = ? oF 3. 135oF = ? K Your Answer: 1 - 328 - 273 = 55 C 2 - (76x 1.8) + 32 = 168.8 F 3 - (135 - 32) / 1.8 = 57.2 C + 273 = 330.2 K 1. 328K - 273 = 55 oC K → oC(make smaller) -273 2. 76oC x 1.8 + 32 = 168.8 oF C → o oF (make larger) x 1.8 + 32 3. 135oF - 32 ÷ 1.8 = 57.2 + 273 = 330.2 K oF → oC →K Question 2 Not yet graded / 10...

CHEM 121 Final Exam Questions and Answers- Portage LearningCHEM 121 Final Exam Questions and Answers- Portage LearningCHEM 121 Final Exam Questions and Answers- Portage LearningCHEM 121 Final Exam Questions and Answers- Portage LearningCHEM 121 Final Exam Questions and Answers- Portage LearningCHEM 121 Final Exam Questions and Answers- Portage LearningCHEM 121 Final Exam Questions and Answers- Portage LearningCHEM 121 Final Exam Questions and Answers- Portage LearningCHEM 121 Final Exam Question...

CHEM 121 Module 1 Exam Questions and Answers - Portage Learning. Complete the two problems below: 1. Convert 1005.3 to exponential form and explain your answer. 2. Convert 4.87 x 10-6 to ordinary form and explain your answer. 1. Convert 1005.3 = larger than 1 = positive exponent, move decimal 3 places = 1.0053 x 103 2. Convert 4.87 x 10-6 =negative exponent =smaller than 1, move decimal 6 places = 0. Question 2 You may find the following resources helpful: Scientific Calculator (Links t...

Title: Organic Synthesis Purpose: In this lab, three carbon based organic compounds were synthesized to determine their true purity. The experiments were done to learn about how to use these compounds’ melting points and infrared spectroscopy to determine their percent yield. Procedure: Experiment 1: Making Acetylsalicylic Acid (aspirin) 1. Obtain a flask. 2. Weigh 2 grams of salicylic acid. 3. Put the 2 grams of salicylic acid into the flask. 4. Put 5 mL of acetic anhydride into a gr...

MODULE 7 ORGANIC CHEMISTRY - PORTAGE LEARNING CHEM 121 EXAM ACTUAL QUESTIONS WITH COMPLETE SOLUTIONS VERIFIED LATEST UPDATE 2024/2025 organic chemistry study of all compounds containing carbon Hydrocarbons the simplest organic materials, containing only the elements hydrogen and carbon aliphatic hydrocarbon A hydrocarbon with carbon atoms joined together in straight or branched chains. Not aromatic. aromatic hydrocarbons hydrocarbons that contain one or more benzene rings 3 types of...

CHEM 121 Lab Report 6 Equilibrium Reactions - Portage Learning

(Portage Learning) CHEM 121 Lab Report 5- Bonding Type by Solubility, Distillation, and Spectroscopy

CHEM 121 FINAL EXAM | Updated Questions and Answers Updated (2024 / 2025) - PORTAGE LEARNING Do the three conversions shown below, showing all work: 1. 328 K = ? oC 2. 76oC = ? oF 3. 135oF = ? K Your Answer: 1 - 328 - 273 = 55 C 2 - (76x 1.8) + 32 = 168.8 F 3 - (135 - 32) / 1.8 = 57.2 C + 273 = 330.2 K 1. 328K - 273 = 55 oC K → oC (make smaller) -273 2. 76oC x 1.8 + 32 = 168.8 oF oC → oF (make larger) x 1.8 + 32 3. 135oF - 32 ÷ 1.8 = 57.2 + 273 = 330.2 K oF → oC →K Question ...