Chem 120 week 8 exam 3 Study guides, Class notes & Summaries

CHEM 120 Week 8 Exam 3 (Units 5, 6, and 7)

Multiple Choice questions: Q 1-40. Highlight or mark the correct answer. (2 point each) 1. The following is a polymer. 2. The following is a naturally occurring polymer. 3. The following is true for Addition polymers. 4. The following is true for condensation polymers. 5. The following is always a reactant in hydrolysis reaction in a cell. 6. Hydrocarbons are made of and 7. As you increase the length of hydrocarbon chain, the molecules becomes more . 8. Ionizing radiation 9. “...

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CHEM 120 Week 8 Final Exam LATEST 2023/2024 UPDATE. SEMESTERS PRIME EXAM (AUGUST 2023) NEWEST EXAM (100% VERIFIED) 1. The name of the compound FES04 is iron sulfate 2. Peptide bonds link the amino acids together to make a primary polypeptide sequence. The bonds are AMIDE 3. If a balloon is filled with helium were heated with a blow dryer , the balloon would increase in volume 4. You are setting up an experiment

CHEM 120 WEEK 8 Final Exam 2023 with correct answers Already graded A+ molarity = moles solute / liters solution 0.25 M = moles NaOH / 0.035 L moles NaOH = 0.00875 moles NaOH 1. (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): (Points : 5) 2. (TCO 1) How many mL are in 3.5 pints? Show your work. (Points : 5) 3.5 pints is equivalent to 1656.116 1 pint = 473.176 ml 3.5 pints* 473.176mL = 1656.116mL 3. (TC...

CHEM 120 Week 8 Final Exam Questions-Answers (Version 1) 2023 UPDATE6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant temperature, determine the volume of helium at 745 mmHg. Show your work. (Points : 5) 8. (TCO 12) If one strand of a DNA double helix has the sequence T T A G C G ...

CHEM 120 WEEK 8 FINAL EXAM 2023 with A+ Grade Solutions 1. (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): (Points : 5) 2. (TCO 1) How many mL are in 3.5 pints? Show your work. (Points : 5) 3.5 pints is equivalent to 1656.116 1 pint = 473.176 ml 3.5 pints* 473.176mL = 1656.116mL 3. (TCO 3) What is the name of the following compound: Zn3P2? (Points : 5) It's Zinc P...

CHEM 120 Week 8 Final Exam - Question Only – Download For Revision Page 1 1. Question: (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): 2. Question: (TCO 1) How many mL are in 3.5 pints? Show your work. 3. Question: (TCO 3) What is the name of the following compound: Zn3P2? 4. Question: (TCO 3) What is the name of the following compound: AgNO3? 5. Question: (TCO 6) Calculate the pressure, in atmospheres, of 2.78 ...