Portage learning chem 104 - Study guides, Class notes & Summaries

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Portage learning CHEM 104 Final Exam Questions and Answers (2024 / 2025) (Verified Complete Answers)
  • Portage learning CHEM 104 Final Exam Questions and Answers (2024 / 2025) (Verified Complete Answers)

  • Exam (elaborations) • 11 pages • 2024
  • Portage learning CHEM 104 Final Exam Questions and Answers (2024 / 2025) (Verified complete Answers)
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Portage Learning CHEM 104 Module 4 Exam
  • Portage Learning CHEM 104 Module 4 Exam

  • Exam (elaborations) • 11 pages • 2024
  • Portage Learning CHEM 104 Module 4 Exam.Question 1 For the cell described by the following cell diagram. Cr (s) | Cr+3 (aq, 1 M) || Al+3 (aq, 1 M) | Al (s) Al+3 + 3e- → Al E0 = - 1.66 v Cr+3 + 3e- → Cr E0 = - 0.73 v (1) The anode half reaction is (2) The cathode half reaction is (3) The overall cell reaction is (4) Show the calculation for the total cell potential (5) State and explain whether the cell is voltaic or electrolytic Your Answer: 1) Cr (s) → Cr+3 (aq) + 3e- 2) Al+3 ...
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Portage Learning CHEM 104 Module 4 Exam
  • Portage Learning CHEM 104 Module 4 Exam

  • Exam (elaborations) • 11 pages • 2024
  • Portage Learning CHEM 104 Module 4 ExamQuestion 1 For the cell described by the following cell diagram. Cr (s) | Cr+3 (aq, 1 M) || Al+3 (aq, 1 M) | Al (s) Al+3 + 3e- → Al E0 = - 1.66 v Cr+3 + 3e- → Cr E0 = - 0.73 v (1) The anode half reaction is (2) The cathode half reaction is (3) The overall cell reaction is (4) Show the calculation for the total cell potential (5) State and explain whether the cell is voltaic or electrolytic Your Answer: 1) Cr (s) → Cr+3 (aq) + 3e- 2) Al+3 (...
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Portage Learning CHEM 104 Module 2 Exam
  • Portage Learning CHEM 104 Module 2 Exam

  • Exam (elaborations) • 10 pages • 2024
  • Portage Learning CHEM 104 Module 2 Exam.Question 1 Identify each of the compounds below as ACID, BASE or SALT on the basis of their formula and explain your answer. (1) Cr(OH)3 (2) HAsO4 (3) CoCO3 Your Answer: 1. base - contains Cr metal + OH polyatomic group 2. acid - contains H + polyatomic group (AsO4) 3. salt - contains Co metal + polyatomic group (CO3) Question 2 For the Brønsted-Lowry acid base reactions shown below, list the stronger acid, stronger base, weaker acid and weake...
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Portage Learning CHEM 104 Module 5 Exam
  • Portage Learning CHEM 104 Module 5 Exam

  • Exam (elaborations) • 8 pages • 2024
  • Portage Learning CHEM 104 Module 5 ExamQuestion 1 Hexene is a hydrocarbon containing (#) carbons and a (type) bond. Your Answer: 6 C=C double Question 2 The compound below is a type of hydrocarbon called a/an . Your Answer: aromatic hydrocarbon Question 3 The compound below is called (#s)-dimethyl . Your Answer: 1,4 cyclohexane
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Portage Learning CHEM 104 Module 5 Exam
  • Portage Learning CHEM 104 Module 5 Exam

  • Exam (elaborations) • 8 pages • 2024
  • Portage Learning CHEM 104 Module 5 ExamQuestion 1 Hexene is a hydrocarbon containing (#) carbons and a (type) bond. Your Answer: 6 C=C double Question 2 The compound below is a type of hydrocarbon called a/an . Your Answer: aromatic hydrocarbon Question 3 The compound below is called (#s)-dimethyl . Your Answer: 1,4 cyclohexane
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CHEM 104 Module 2: Exam (Portage learning)
  • CHEM 104 Module 2: Exam (Portage learning)

  • Exam (elaborations) • 18 pages • 2023
  • Identify each of the compounds below as ACID, BASE or SALT on the basis of their formula and explain your answer. (1) MgCl (2) HClO (3) Cu(OH) 2 4 2 1.) MgCl2 This is a salt because Mg ( metal) and Cl is a nonmetal 2.) HCIO4 This is a Acid because H infront and Cl is a nonmetal 3) Cu(OH)2 This is a BASE because it has OH and the Cu is a metal MgCl Salt Contains Metal (Mg) + Nonmetal (Cl) HClO Acid Contains H + Polyatomic group (ClO ) Cu(OH) Base Contains Metal (Cu) + OH Polya...
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Portage Learning CHEM 104 Module 3 Exam
  • Portage Learning CHEM 104 Module 3 Exam

  • Exam (elaborations) • 7 pages • 2024
  • Portage Learning CHEM 104 Module 3 Exam.Question 1 Show the calculation of the molar solubility (mol/L) of BaF2, Ksp of BaF2 = 1.0 x 10-6. Your Answer: Ksp = [Ba+2] [F-]2 = 1.0x10-6 1.0x10-6 = [s] [2s]2 1.0x10-6 = 4s3 s = 6.3x10-3 mol/L Question 2 Show the calculation of the Ksp of MnS if the solubility of MnS is 0.0001375 g/100 ml. MW of MnS = 87.01 MnS (s) Mn+2 (aq) + S-2 (aq) Your Answer: molar solubility of MnS = (0.0001375 g/100 ml) x (1000 mL) x (1 mol/87.01 g MnS) molar solub...
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