Chapter 3 chem 120 - Study guides, Class notes & Summaries

Chem. 120: week 4 Question 1: (TCO 6) A sample of helium gas occupies 520 mL at 79 mmHg. For a gas sample at constant temperature, determine the volume of helium at 45 mmHg. Student Answer: Boyles Law P1V1=P2V2 Temp is constant 79 mmHg x 520 mL= 45 mmHg x V2 41080= 45 mmHg x V2 912.88 mL=V2 Instructor Explanation: Chapter 6; Using Boyle’s law, P1V1 = P2V2. We have V1 (520 mL), P1 (79 mmHg) and P2 (45 mmHg). We want to determine V2, so V2 = (P1 x V1)/P2 = (520 mL * 79 ...

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