Nao volume 4 - Study guides, Class notes & Summaries
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CHEM 120 Week 8 Final Exam (Solved Q & A) | Highly Rated Paper | Already Graded A+
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6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) Using Charles’ Law, ( V1/T1) = (V2/T2). First, convert temperature to KELVIN (T1 = t1 +273) Thus, T1 = 95 + 273 = 368. We have V1 (165 mL) & T2 = (25 + 273) = 298. V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 0 7 Short 16 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant tempera...
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NAO VOLUME IV EXAM QUESTIONS AND ANSWERS
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NAO VOLUME IV EXAM QUESTIONS AND 
ANSWERS 
The amount of reflection of each surface of CR-39 plastic lenses is approximately: - ANSWER-4% 
The absorption of light in lenses is classified by two variables. What are they? - ANSWER-Tint and 
lens transmission 
The denser the tint in a lens, the _____: - ANSWER-Less transmission of light through the lens 
Standard transmission in sunlenses should range between: - ANSWER-15% and 30% 
If a person has exposure to sunlight at least 2 hours or more durin...
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NAO Volume 2 Exam Questions and Answers
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NAO Volume 2 Exam Questions and 
Answers 
Absorption - ANSWER-in terms of light and lens- when a ray of light enters a lens some of the light 
will not completely travel through the lens 
Deviation (Angle of) - ANSWER-the angle a ray of light is changed from its original path 
Diffuse Relection - ANSWER-a reflection from a rough surface- the reflection does not produce a 
clear image 
Incidence (Angle of) - ANSWER-the angle which a ray of light makes the surface of a refracting 
medium 
Reflecti...
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CHEM 120 Week 8 Final Exam graded A
- Exam (elaborations) • 23 pages • 2021
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CHEM 120 Week 8 
Final Exam 
1.(TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant 
pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) 
Using Charles’ Law, (V1/T1) = (V2/T2). 
First, convert temperature to KELVIN (T1 = t1 +273) 
Thus, T1 = 95 + 273 = 368. 
We have V1 (165 mL) & T2 = (25 + 273) = 298. 
V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL. 
0 7 Short 16 
2.(TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. F...
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