Cs6515 exam 1 - Study guides, Class notes & Summaries
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cs6515 Exam 1 Prep with complete solution
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cs6515 Exam 1 Prep with complete solution
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CS6515 - Exam 1 with complete solution
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CS6515 - Exam 1 with complete solution
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CS6515 - Algorithms- Exam 1 with complete solution
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CS6515 - Algorithms- Exam 1 with complete solution
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CS6515 - Algorithms- Exam 1 | Questions and Verified Answers | Latest Update 2024/2025 | Graded A+
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CS6515 - Algorithms- Exam 1 | 
Questions and Verified Answers | 
Latest Update 2024/2025 | 
Graded A+ 
Steps to solve a Dynamic Programming Problem - Answer -1. Define the 
Input and Output. 
2. Define entries in table, i.e. T(i) or T(i, j) is... 
3. Define a Recurrence relationship - Based on a subproblem to the 
main problem. (hint: use a prefix of the original input 1 < i < n). 
4. Define the Pseudocode. 
5. Define the Runtime of the algorithm. Use Time Function notation 
here => T(n...
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CS6515 Exam 2 | Questions and Correct Answers | Latest Update 2024/2025 | Graded A+
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CS6515 Exam 2 | Questions and 
Correct Answers | Latest Update 
2024/2025 | Graded A+ 
Basic Properties of Trees - Answer -Tree's are undirected, connected 
and acyclic that connect all nodes. 
1. Tree on n vertices has (n-1) edges -> would have a cycle otherwise 
(more than n-1 edges means cycle) 
2. In tree exactly one path between every pair of vertices (otherwise it's 
not connected) 
- More than 1 path implies cycle 
- less than 1 path implies not connected 
3. Any connected G(V, E) wi...
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CS6515 Exam 2 Questions and answers
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CS6515 Exam 2 Questions and answers 
If graph G has more than |V | − 1 edges, and there is a unique heaviest edge, 
then this edge cannot be part of a minimum spanning tree - ANSWER-False, 
because the unique heaviest edge may not be part of a cycle 
If G has a cycle with a unique heaviest edge e, then e cannot be part of any MST. 
- ANSWER-True, if the unique heaviest edge is part of a cycle then it will be 
removed first. 
Let e be any edge of minimum weight in G. Then e must be part of some...
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CS6515 Exam Bundle Package | Questions and Answers | Latest 2024/2025
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CS6515 Exam Bundle Package | Questions and Answers | Latest 2024/2025. Actual tests, Exam 1, Exam 2
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CS6515 - Algorithms- Exam 1 Complete Questions And Solutions latest
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How do you tell if a graph has negative edges? - ANSWER-when fitting graph on 
a table, if the number of moves decreases the w() from edge to edge, then there 
is a negative edge; 
check from 1 to n 
Why are all pairs Dist(y,z) n^2? - ANSWER-Because it builds a two dim table! 
What is the run time of bellman ford algorithm? 
How about if you had to do it for all edges? - ANSWER-O(nm) 
O(n^2m) 
Floyd-Warshall run time? - ANSWER-O(n^3) 
What is the base case for the bellman ford algorithm? - ANSWE...
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CS6515 - Algorithms- Exam 1 Questions and Correct Answer
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CS6515 - Algorithms- Exam 1 
Questions and Correct AnswerCS6515 - Algorithms- Exam 1 
Questions and Correct AnswerCS6515 - Algorithms- Exam 1 
Questions and Correct AnswerCS6515 - Algorithms- Exam 1 
Questions and Correct AnswerCS6515 - Algorithms- Exam 1 
Questions and Correct AnswerCS6515 - Algorithms- Exam 1 
Questions and Correct AnswerCS6515 - Algorithms- Exam 1 
Questions and Correct AnswerCS6515 - Algorithms- Exam 1 
Questions and Correct AnswerCS6515 - Algorithms- Exam 1 
Questions and C...
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cs6515 Exam 1 Prep questions and answers
- Exam (elaborations) • 10 pages • 2024
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Knapsack without repetition - ANSWER-k(0) = 0 
for w = 1 to W: 
if w_j >w: k(w,j) = k(w, j - 1) 
else: K(w,j) = max{K(w, j -1),K(w - w_j, j -1) + v_i} 
knapsack with repetition - ANSWER-knapsack repeat(w_i....w_n, w_i... w_n, B) 
k(0) = 0 
for i = 1 to n 
if w_i <= b & k(b) <v_i + K(b-w_i) 
then k(b) = v_i + K(b-w_i) 
Longest Increasing Subsequence - ANSWER-LIS(a_1.... a_n) 
for i = 1 to n 
L(i) = 1 
for j = 1 to n -1 
if a_j < a_i & L(i) < 1 + L(j) 
L(i) = 1 + L(j) 
max = 1 
for ...
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