Chem133 week 4 quiz - Study guides, Class notes & Summaries

1. Question: Which one of the following is most likely to be an ionic compound? 2. Question: The phosphorus atom in PCl3 would be expected to have a 3. Question: The phosphorus atom in PCl3 would be expected to have a give CH3Cl and hydrogen chloride. 4. Question: How many of the following molecules have no dipole moment? 5. Question: Atoms having equal or nearly equal electronegativities are expected to form 6. Question: Element A has an electronegativity of 0.8 and element B has an electr...

1. Question: If 0.274 moles of a substance weighs 62.5 g, what is the molar mass of the substance, in units of 2. Question: What volume of 18 M sulfuric acid must be used to prepare 1.80 L of 0.215 M H2SO4? 3. Question: What is the molecular mass of Br2? 4. Question: What is the molar concentration of sulfate ions in a 0.150 M Na2SO4 solution? 5. Question: How many moles of hydrogen chloride are contained in a 52.6 g sample of this gas? 6. Question: 1.00 mole of O2 contains the same number ...

1. Question: Which one of the following is most likely to be an ionic compound? 2. Question: The phosphorus atom in PCl3 would be expected to have a 3. Question: The phosphorus atom in PCl3 would be expected to have a give CH3Cl and hydrogen chloride. 4. Question: How many of the following molecules have no dipole moment? 5. Question: Atoms having equal or nearly equal electronegativities are expected to form 6. Question: Element A has an electronegativity of 0.8 and element B has an electr...

1. Question: If 0.274 moles of a substance weighs 62.5 g, what is the molar mass of the substance, in units of 2. Question: What volume of 18 M sulfuric acid must be used to prepare 1.80 L of 0.215 M H2SO4? 3. Question: What is the molecular mass of Br2? 4. Question: What is the molar concentration of sulfate ions in a 0.150 M Na2SO4 solution? 5. Question: How many moles of hydrogen chloride are contained in a 52.6 g sample of this gas? 6. Question: 1.00 mole of O2 contains the same number ...