Chem 103 exam answers - Study guides, Class notes & Summaries

Chem 103 Module 1 to 6 Exam with Verified answers (100 OUT OF 100) Portage learning (Latest Update) MODULE 1 EXAM Question 1 Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smalle...

CHEM 103 Final Exam (100 out of 100) Questions and Answers (New Update) Verified Elaborations.

CHEM 103 Lab Exam 4 (100 out of 100) Questions and Verified Answers (Portage Learning)

CHEM 103 MODULE 1 TO 6 EXAM LATEST 2022-2023 QUESTIONS & CORRECT ANSWERS PORTAGE LEARNING|COMPLETE AGRADE

CHEM 121 Module 1 Exam Questions and Answers - Portage Learning. Complete the two problems below: 1. Convert 1005.3 to exponential form and explain your answer. 2. Convert 4.87 x 10-6 to ordinary form and explain your answer. 1. Convert 1005.3 = larger than 1 = positive exponent, move decimal 3 places = 1.0053 x 103 2. Convert 4.87 x 10-6 =negative exponent =smaller than 1, move decimal 6 places = 0. Question 2 You may find the following resources helpful: Scientific Calculator (Links t...

CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1.Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2.Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0. Question 2 Click this link to access the Periodic Table. This may be helpful throughout the exam. Using the following info...

CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Show the calculation of the mass of a 18.6 ml sample of freon with density of 1.49 g/ml 2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5 ml. 1. M = D x V = 1.49 x 18.6 = 27.7 g 2. D = M / V = 26.3 / 30.5 = 0.862 g/ml Question 5 Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. 3.0600 contains ? significant figures. 2. 0.0151 contains ? significant figu...

Chem 103 Mod 3 Exam (Latest Update) Questions and Answers | 100% CORRECT Elaborations

The unit “m” stands for _______ in this experiment. 2. (4 points) Why was warming data used for estimating the freezing/melting point of the cyclohexane? 3. (3 points) How much of the cyclohexane solvent was placed in the test? 1.) molarity 2.) It is considered reliable. It is a dependable predicator of the freezing/melting point of a substnace. it can determine the temperatures when the change occurs. 3.) 10 mL of cyclohexane 1. molality 2. Solids tend to supercool, which gives fa...