Chem 103 exam 6 - Study guides, Class notes & Summaries
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Exam CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A|
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Exam 
CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A| Exam 
CHEM 103 Final Exam (Version-1, Latest-2023)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |100 % Correct Q & A| 
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Portage Learning / CHEM 103 / Module 1 to 6 Exam answers 2023|2024 UPDATED A+ RATED
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Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
1. Convert 845.3 to exponential form and explain your answer. 
2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 
1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places 
= 8.453 x 102 
2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 
places = 0. 
Question 2 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. ...
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Chem 103 Module 1 to 6 Exam answers Portage learning latest complete update
- Exam (elaborations) • 34 pages • 2024
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Chem 103 Module 1 to 6 Exam answers Portage learning latest complete update 
 
 
 
MODULE 1 EXAM 
Question 1	 Click this link to access the Periodic Table. This may be helpful throughout the exam. 
1.	Convert 845.3 to exponential form and explain your answer. 
2.	Convert 3.21 x 10-5 to ordinary form and explain your answer. 
 
 
1.	Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places 
= 8.453 x 102 
2.	Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal...
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Chem 103 Lab exam 6 Questions and Answers (100% Correct Elaborations) Portage Learning
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Chem 103 Lab exam 6 Questions and Answers (100% Correct Elaborations) Portage Learning
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CHEM 103 MODULE 1 TO 6 EXAM LATEST 2022-2023 QUESTIONS & CORRECT ANSWERS PORTAGE LEARNING|COMPLETE AGRADE
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CHEM 103 MODULE 1 TO 6 EXAM LATEST 2022-2023 
QUESTIONS & CORRECT ANSWERS PORTAGE 
LEARNING|COMPLETE AGRADE
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CHEM 121 Module 1 Exam Questions and Answers - Portage Learning.
- Exam (elaborations) • 7 pages • 2024
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CHEM 121 Module 1 Exam Questions and Answers - Portage Learning. Complete the two problems below: 
1. Convert 1005.3 to exponential form and explain your answer. 
2. Convert 4.87 x 10-6 to ordinary form and explain your answer. 
1. Convert 1005.3 = larger than 1 = positive exponent, move 
decimal 3 places = 1.0053 x 103 
2. Convert 4.87 x 10-6 =negative exponent =smaller than 1, move 
decimal 6 places = 0. 
Question 2 
You may find the following resources helpful: 
Scientific Calculator (Links t...
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CHEM 103: GENERAL ORGANIC CHEMISTRY Module 1 to 6 Exams and Final Exam with Verified answers Bundle | Portage learning (Latest Update)
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CHEM 103: GENERAL ORGANIC CHEMISTRY Module 1 to 6 Exams and Final Exam with Verified answers Bundle | Portage learning (Latest Update)
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)
- Exam (elaborations) • 35 pages • 2023
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Convert 845.3 to exponential form and explain your answer. 
2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 
1.Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places 
= 8.453 x 102 
2.Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 
places = 0. 
Question 2 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
Using the following info...
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CHEM 103: General Chemistry I module exam 1-6 and final exam portage learning
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CHEM 103: General Chemistry I module exam 1-6 and final exam portage learning
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning)
- Exam (elaborations) • 35 pages • 2023
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CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Show the calculation of the mass of a 18.6 ml sample of freon with 
density of 1.49 g/ml 
2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5 
ml. 
1. M = D x V = 1.49 x 18.6 = 27.7 g 
2. D = M / V = 26.3 / 30.5 = 0.862 g/ml 
Question 5 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
1. 3.0600 contains ? significant figures. 
2. 0.0151 contains ? significant figu...
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