Chem 102 Study guides, Class notes & Summaries

oxidation of an aldehyde - ANSWER-carboxylic acid reaction of carboxylic acid with strong base - ANSWER-carbohlate salt dehydration of carboxylic acid with an alcohol - ANSWER-ester acid hydrolysis of an ester - ANSWER-carboxylic acid and alcohol base hydrolysis of an ester - ANSWER-carboylate salt and alcohol hydration of a carboxylic acid - ANSWER-acid anhydride amines react with acids to - ANSWER-amine salts (ammonium slats) reaction of NH3 with an alcohol - ANSWER-primar...

Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0. Question 2 Click this link to access the Periodic Table. This may be helpful throughout the exam. ...

MNG2602 Assignment 1 (COMPLETE ANSWERS) Semester 2 2024 - DUE 28 August 2024 ; 100% TRUSTED Complete, trusted solutions and explanations. For assistance, Whats-App Question 1 Consider the “human capital” highlights for 2023 presented on page 6 of the IAR. Which two sources of diversity are evident in this section? (2 marks) Question 2 Consider the Dis-Chem brand in the group profile on page 8 of the IAR. Identify and explain (theoretically) the corporate-level strategy that the Dis-Chem g...

Chem 103 Module 1 to 6 Exam with Verified answers (100 OUT OF 100) Portage learning (Latest Update) MODULE 1 EXAM Question 1 Click this link to access the Periodic Table. This may be helpful throughout the exam. 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = smalle...

P=F/A - Answer-pressure equals force divided by area Boyle's Law - Answer-they volume of a fixed quantity of gas at constant temperature is INVERSELY proportional to the pressure Boyle's Law equation - Answer-PV=K Charles's Law - Answer-The volume of a fixed amount of gas at a constant pressure is directly proportional to its absolute temperature Charles's Law Equation - Answer-V/T=K Avogadro's Law - Answer-The volume of a gas at constant temperature and pressure is directly proport...

The average rate of appearance of [NH3] is 0.215 M/s. Determine the average rate of disappearance of [H2]. N2(g) + 3H2(g) -> 2NH3(g) - Answer--0.323 M/s Use the following experimental data to determine the rate law expression and the rate constant K for the following chemical equation; 2NO(g) + O2(g) -> N2O4(g) .100M ~ .100M ~ 1.25 x 10^-4 M/s .200M ~ .100M ~ 5.00 x 10^-4 M/s .100M ~ .200M ~ 2.50 x 10^-4 M/s - Answer-Rate = K[NO]^2[O2] K = 0.125 M^-2 s^-1 Which of the following w...

Intramolecular - Answer-forces holding atoms within molecules intermolecular - Answer-forces of attraction between molecules Ion-ion - Answer-strongest bonds; high melting temps; involve cations and anions ion-permanent dipole - Answer-salts + polar molecules (water); metal ions with water or other polar mol. dipole-dipole - Answer-bind molecules with PERMANENT dipoles; seen in BPs of simple molecules hydrophilic molecules - Answer-attraction to water; polar; O-H or N-H bonds; soluble in w...

CHEM 1020 Final Exam Questions And Answers With Verified Solutions CHEM 1020 Final Exam Questions And Answers With Verified Solutions

CHEM 103 Module 1 to 6 Exam Questions and Answers (Portage Learning) Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1.Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2.Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0. Question 2 Click this link to access the Periodic Table. This may be helpful throughout the exam. Using the following info...