Bch 369 chapter 7 - Study guides, Class notes & Summaries

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BCH 369 CHAPTER 7 TEST QUESTIONS WITH ANSWERS ALL REVISED AND UPDATED
  • BCH 369 CHAPTER 7 TEST QUESTIONS WITH ANSWERS ALL REVISED AND UPDATED

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  • BCH 369 CHAPTER 7 TEST QUESTIONS WITH ANSWERS ALL REVISED AND UPDATED random mechanism - Answer-A multisubunit reaction without a compulsory order of substrate binding to the enzyme. ordered mechanism - Answer-A multisubunit reaction with a compulsory order of substrate binding to the enzyme. Ping pong mechanism - Answer-An enzymatic reaction in which one or more products are released before all the substrates have bound to the enzyme. allosteric enzyme - Answer-1 cooperativity - A...
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BCH 369 chapter 7 Test with Questions Solved 100% Correct | Latest Update
  • BCH 369 chapter 7 Test with Questions Solved 100% Correct | Latest Update

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  • diffusion controlled limit - Answer The theoretical maximum rate of an enzymatic reaction in solution, about 10^8 to 10^9 M^-1 * s^-1 catalytic perfection - Answer A state achieved by an enzyme that operates at the diffusion-controlled limit. Lineweaver-Burk plot - Answer A rearrangement of the michaelis menton equation that permits the determination of KM and Vmax from a linear plot.
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BCH 369 chapter 7 Test with Questions Solved 100% Correct | Latest Update
  • BCH 369 chapter 7 Test with Questions Solved 100% Correct | Latest Update

  • Exam (elaborations) • 7 pages • 2024
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  • BCH 369 chapter 7 Test with Questions Solved 100% Correct | Latest Update
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BCH 369 chapter 7 EXAM PREP WITH  COMPLETE SOLUTION
  • BCH 369 chapter 7 EXAM PREP WITH COMPLETE SOLUTION

  • Exam (elaborations) • 5 pages • 2024
  • BCH 369 chapter 7 EXAM PREP WITH COMPLETE SOLUTION
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BCH 369 CHAPTER 7 TEST QUESTIONS WITH ANSWERS ALL REVISED AND UPDATED
  • BCH 369 CHAPTER 7 TEST QUESTIONS WITH ANSWERS ALL REVISED AND UPDATED

  • Exam (elaborations) • 4 pages • 2024
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  • BCH 369 CHAPTER 7 TEST QUESTIONS WITH ANSWERS ALL REVISED AND UPDATED Michaelis-Menten equation - Answer-A mathematical expression that describes the activity of an enzyme in terms of the substrate concentration ([S]), the enzyme's maximal velocity (Vmax), and its michaelis constant (Km): Vo = Vmax [S]/(Km + [S]). catalytic constant (Kcat) - Answer-The ratio of the maximal velocity (Vmax) of an enzyme-catalyzed reaction to the enzyme concentration. Also called a turnover number. Turnover...
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