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WGU C949 Data Structures and Algorithms I Focused on Unit 07 and 22 Objective Assessment Guide Exam Questions and Already graded Solutions and Assured Satisfactions 2024/2025$10.99
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WGU C949 Data Structures and Algorithms I Focused on Unit 07 and 22 Objective Assessment Guide Exam Questions and Already graded Solutions and Assured Satisfactions 2024/2025
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WGU C949 Data Structure and Algorithm
Institution
WGU C949 Data Structure And Algorithm
WGU C949 Data Structures and Algorithms I Focused on Unit 07 and 22 Objective Assessment Guide Exam Questions and Already graded Solutions and Assured Satisfactions 2024/2025
Memory allocation - correct answer the process of an application requesting and being granted memory.
Memory deallocat...
WGU C949 Data Structures and Algorithms I
Focused on Unit 07 and 22 Objective
Assessment Guide Exam Questions and
Already graded Solutions and Assured
Satisfactions 2024/2025
Memory allocation - correct answer the process of an
application requesting and being granted memory.
Memory deallocation - correct answer the act of freeing the
memory that stores variables or objects in a program.
Reference count - correct answer an integer counter that
represents how many variables reference an object.
A linked-list implementation of a stack guarantees constant time
performance but requires more space than an array
implementation. - correct answer TRUE
Both implementations of pop and push guarantee constant time
performance. Linked lists require additional memory (space) for
storing a reference to the next node.
An algorithm that uses 12n2 + 4n log n operations is a ∼n2
algorithm. - correct answer FALSE
It is a ∼ 12n2 algorithm.
Big-Oh notation is more precise than tilde notation at describing
the growth of a function. - correct answer FALSE
, Big-Oh notation only provides an upper bound on the growth rate
of a function. Tilde approximation approaches the original
function as N grows.
When implementing the Comparable interface, you should make
sure that your implementation of the compareto() method
specifies a total order over the objects. - correct answer
TRUE
When implementing the Comparable interface, you should make
sure that your implementation of the compareto() method
specifies a total order over the objects.
Mergesort - correct answer Stable and fast
Quicksort - correct answer Fast general-purpose sort
Shellsort - correct answer Not analyzed
Insertion sort - correct answer Works well with order
Selection sort - correct answer Optimal data movement
3-way quicksort - correct answer Works well with duplicates
Heapsort - correct answer Optimal time and space
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