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Summary AP Physics I: Kinematics in 1 Dimension
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Provides a summary of 1-d kinematics and the equations used for solving problems.
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AP Physics I 1D Kinematicsscalers: a quantity that only contains magnitude variables & units:
ex: 4m/s x = horizontal position ex: 7m
vectors: a quantity that has magnitude and direction y = vertical position ex: 34cm
v = velocity ex: 7 m/s
ex: -6 m/s
v₀= initial velocity
distance: how far an object has traveled
v₀x = initial horizontal velocity
displacement: how far an object is from where it started v₀y = initial vertical velocity
ex: → → → 4m a = acceleration -7 m/s² or g = -9.80 m/s²
←←← ← 7m t = time ex: 6s
distance = 11m | displacement = -3m significant figures ‘sig figs’ :
Δx=x-x₀ or change in x = final position - initial position -all non zero numbers are significant
-zeros between non-zeros are significant
speed: the rate of change of an object with no regard to direction
-zeros to the right are significant
velocity: the rate of change of an object with a direction 23,703 = 5 sig figs 0.47 = 2 sig figs
speed: distance velocity: displacement 0.0876 = 4 sig figs 675 = 3 sig figs
time time equations:
acceleration: rate of change in velocity with a direction
position equation:Δx=v₀t+½at²
Δvelocity free fall position equation: Δy=v₀yt + ½at²→ Δy= ½at²
Δtime ‘velocity’ equation: v²=v₀² + 2a (Δx)
displacement equation: v= v₀ + at
conversions: ‘magic box’ conversion (ft → inches) closing velocity: object₁ v + object₂ v = closing velocity
4ft 12in 48 inches ex: 110 m/s + 200 m/s = 310 m/s
1 1ft 1
basic conversions:
1 ft = 12 in 1 yd = 3 ft
1 m = 100 cm 1 km = 1000 m
1 cm = 10 mm 1 in = 2.54 cm
1 mi = 1,609 m 1 mi = 5,280 ft
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