1.1. The building in Fig. P1.1 is used for general office space. The slab is 8 in. thick. The beams
are 12 in. wide and have a total depth of 18 in., the bay dimensions are 18.5 ft in the X direction
and 21 ft in the Y direction, and the superimposed service dead load is 18 psf. Calculate the
slab service load in psf and the interior beam service load in klf. (Solution: qs = 175 psf,
ws = 3.36 klf.)
SOLUTION
From table 1.1 Office load ql : 50 psf
Concrete unit weight c : 150 pcf
t : 8 in
Slab load qd : t c 100 psf
Superimposed dead load qsdl : 25 psf
Service load qs : ql qd qsdl 175 psf
The beam length is 21 feet and the tributary width is 18.5 ft. The beam is 12 18 in. of which
10 in. is below the slab.
wbeam : (18 in t ) 12 in c 125 plf
ws : 18.5 ft ql 18.5 ft (qd qsdl ) wbeam 3363 plf ws 3.36 klf
1.2. The building in Fig. P1.1 is used for general office space. The slab is 8 in. thick. The beams
are 12 in. wide and have a total depth of 18 in., the bay dimensions are 18.5 ft in the X direction
and 21 ft in the Y direction, and the superimposed service dead load is 25 psf. Calculate the
factored axial column load transferred to column C3 on the 3 rd floor. (Solution: Pu 92.5 kips.)
SOLUTION c : 150 pcf ql : 50 psf qsdl : 25 psf
Slab load t : 8 in qd : t c 100 psf
Tributary area At : 18.5 ft 21 ft 388.5 ft 2
wbeam : (18 in t ) 12 in c 125 plf
Pu : 1.6 At ql 1.2 At (qd qsdl ) 1.2 wbeam 21 ft 92.5 kip
1.3. The building in Fig. P1.1 is used for general office space. The slab is 8 in. thick. The beams
are 12 in. wide and have a total depth of 18 in., the bay dimensions are 18.5 ft in the X direction
and 21 ft in the Y direction, and the superimposed service dead load is 25 psf. Calculate the slab
factored load in psf and the beam factored load in klf. Comment on your solution in comparison
with Problem 1.1.
SOLUTION c : 150 pcf ql : 50 psf qsdl : 25 psf
Slab load t : 8 in qd : t c 100 psf
qu : 1.6 ql 1.2 (qd qsdl ) 230 psf
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