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CHM 142 Exam 3 Review questions and answers Graded A correct solution 2024/2025
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CHM 142 Exam 3 Review questions and answers Graded A correct solution 2024/2025
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CHM 142 Exam 3 ReviewGiven the pKa's of several polyprotic acids choose the strongest acid among the ions
given below.
H3PO4: pKa1=2.16, pKa2=7.19, pKa3=12.32
H3AsO4: pKa1=2.26, pKa2=6.77, pKa3=11.29
H2SO3: pKa1=1.77, pKa2=7.21
H2CO3: pKa1=6.37, pKa2=10.33
> HCO3-
> H2AsO4-
> H2PO4-
> HPO42-
> HSO3-
H2AsO4-
Which of the following is the weakest base?
> (CH3CH2)2NH (pKb = 3.07)
> NH2OH (pKb = 7.97)
> (CH3CH2)3N (pKb = 3.25)
> CH3CH2NH2 (pKb = 3.25)
> (CH3)3N (pKb = 4.19)
NH2OH (pKb = 7.97 )Read More
Which of the following ions have negligible tendency to accept protons in water?
BrO-, Cl-, NO3-, PO43-, SO32-
> only Cl-, PO33- and SO32-
> only BrO- and NO3-
> only Cl- and NO3-
> only BrO-, PO33- and SO32-
> only PO43- and SO32-
only Cl- and NO3-
The pH of a 5.64 x 10-2 M solution of a weak base was found to be 11.72. Using this
information find the value of pKb for this base.
3.27
Calculate the pH of a 3.72 x 10-2 M solution of ammonia, NH3 (Kb=1.8 x 10-5).
10.91
The acid ionization constant (Ka) for HI is estimated to be 1 x 109. What is the value of
Kb for I-?
1 x 10^-23
An aqueous solution of NH4Cl will be
acidic, because of the hydrolysis of NH4+ ions.
basic, because of the hydrolysis of Cl- ions.
basic, because of the ionization of NH3.
basic, because of the hydrolysis of NH4+ ions.
acidic, because of the hydrolysis of Cl- ions.
, acidic, because of the hydrolysis of NH4+ ions.
Which of the following salts will form basic solution(s) in water?
NaBr,, NaF, NaNO3, Na3PO4, Na2SO3
NaF, Na3PO4 and Na2SO3
Which of the following salts will form acidic solution(s) in water?
CrCl3, K2CO3, KI, NH4NO3, SrS
CrCl3 and NH4NO3
Given the pKa's of several triprotic and diprotic acids choose the strongest base among
the ions given below.
H3AsO4: pKa1 = 2.26, pKa2 = 6.77, pKa3 = 11.29
H3PO4: pKa1 = 2.12, pKa2 = 7.21, pKa3 = 12.38
H2SO3: pKa1 = 1.77, pKa2 = 7.21
H2CO3: pKa1 = 6.37, pKa2 = 10.33
H2SeO3: pKa1 = 2.64, pKa2 = 8.28
> H2PO4-
> HSO3-
> H2AsO4-
> HSeO3-
> HCO3-
HCO3-
Calculate the pH of a 0.364 M aqueous solution of sodium acetate (CH3COONa). For
CH3COOH, Ka = 1,8 x 10-5.
9.15
Using the pKa's of five weak acids choose the salt of one of them that will have the
highest pH if solutions of the same concentration were compared.
HBrO: pKa = 8.60
HClO: pKa = 7.52
HIO: pKa = 10.64
HF: pKa = 3.17
HCN: pKa = 9.31
> NaCN
> NaF
> NaIO
> NaBrO
> NqClO
NaIO
Which of the following is the weakest acid?
> HBrO
> HClO3
> HClO
> HBrO2
> HClO2
HBrO
Arrange the following acids:
HBrO, HIO, and HI
in order of increasing strength (weakest to strongest).
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