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PORTAGE LEARNING CHEM 103 FINAL EXAM $10.99   Add to cart

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PORTAGE LEARNING CHEM 103 FINAL EXAM

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PORTAGE LEARNING CHEM 103 FINAL EXAM 1. Convert 845.3 to exponential form and explain your answer. 2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places = 8.453 x 102 2. Convert 3.21 x 10-5 = negative exponent = ...

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  • October 18, 2024
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CHEM z103
zFINAL zEXAM

Question z 1
zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
z z z z z z z z z z z z z z z z z z z z z z z z z z z Click zthis z link z to zaccess z the z Periodic
z Table. z This z may z be zhelpful z throughout zthe zexam.




1. Convert z845.3 zto zexponential zform zand zexplain zyour zanswer.


2. Convert z3.21 zx z 10-5 z z zto zordinary z form zand z explain z your zanswer.
1. Convert z845.3 z= zlarger zthan z1 z= zpositive zexponent, zmove zdecimal z2
zplaces
= z8.453 z x z102


2. Convert z3.21 zx z 10-5 z z z= z negative z exponent z = zsmaller zthan z 1, z move
z decimal z 5 zplaces z= z0.0000321



Question z2

, Click zthis z link zto z access z the z Periodic z Table. z This z may zbe z helpful
z throughoutzthe zexam.




Do zthe z conversions z shown z below, z showing z all z work:


1. 246oK z = z? z oC
2. 45oC z= z? z oF
3. 18oF z = z? zoK


1. 246oK z- z273 z = z-27 zoC o
K z→ z oC z(make z smaller)
-273
2. 45oC zx z1.8 z+ z32 z = z113 zoF o
C z→ z oF z(make zlarger) zx
1.8 z+ z32
3. 18oF z- z32 z÷ z 1.8 z = z-7.8 z + z 273 z z = z265.2 zoK o
F z → z oC z → z o K


Question z 3
zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz zzz
z z z z z z z z z z z z z z z z z z z z z z z z z z z Click zthis z link z to zaccess z the z Periodic
z Table. z This z may z be zhelpful z throughout zthe zexam.




Show zthe zcalculation zof zthe znumber zof zmoles zin zthe zgiven zamount zof zthe
zfollowing zsubstances. zReport zyour zanswer zto z3 zsignificant zfigures.




1. Moles z= zgrams z/ zmolecular zweight z= z12.0 z/ z132.15 z= z0.0908 zmole


2. Moles z= zgrams z/ zmolecular zweight z= z15.0 z/ z179.17 z= z0.0837 zmole


Question z 4
zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
z z z z z z z z z z z z z z z z z z z z z z z z z z z Click zthis z link z to zaccess z the z Periodic
z Table. z This z may z be zhelpful z throughout zthe zexam.




Show zthe zcalculation zof zthe zpercent zof zeach zelement zpresent zin zthe
zfollowingzcompounds. zReport zyour zanswer zto z2 zplaces zafter zthe zdecimal.

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