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Math 425 - Exam 2 All Answers Correct

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Math 425 - Exam 2 All Answers Correct 40% of students at a school have brown hair, 25% own a red car (these are independent events). from a group of 2 students, we know that at least one of them has brown hair and owns a car. what is the probability that both own a car? What kind of problem...

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  • October 16, 2024
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Math 425 - Exam 2 All Answers Correct

40% of students at a school have brown hair, 25% own a red car (these are independent events). from a
group of 2 students, we know that at least one of them has brown hair and owns a car. what is the
probability that both own a car?



What kind of problem is this and how do you solve it?

What operation do you perform for independent events? ✅Conditional Probability, use multiplication
with independent events



Solution: Draw a diagram that shows conditioning event and the event of interest which is the
intersection of the conditioning event. another problem example is the boy born on tuesday.



numerical answer: 0.04/0.19



25% of people have a disease gene R, if one has R one has a 30% change of getting the disease during
any period of 10 years (each 10 year period is an independent event). if one does not have R, they have
a 10% chance of getting the disease in during the first 10 year period. what is the probability they won't
get it in the next 10 years



What kind of problem is this?

What formula us used here? ✅Insurance problem, Bayes formula, there are several forms of it: normal
and reverse form



P(E) = P(E/F) * P(F) + P(E/F^C) * (1 - P(F))



P(F/E) = P(E/F) * P(F) / P(E/F) * P(F) + P(E/F^C) * (1 - P(F))



Solution:

P(R) = 0.25

, P(D1^C/R) = 0.7

P(D1^C/R^C) = 0.9



P(R/D1^C) = (0.7)(0.2) / (0.7)(0.25) + (0.9)(0.75)



P(D2^C/D1^C) = (0.7)(7/43) + (0.9)(36/43)



if a better believes that a team has an 80% probability of winning a game then the payout on a $1 bet is
$1.2 (net winning is 0.2 cents) should they bet on the team to win?



What type of problem is this? ✅Odds problem

Odds formula: O(E) = P(E) / 1 - P(E)



Solution:

O(E) = 0.8/0.2 = 4

take the reciprocal to get what the total winning are to break even.

4 --> 1/4

to break even need:1.25



therefore the better should not place a bet



internet servers are linked as follows

branch one in series, S1, S2

branch 2, S3.

prob of S1 being open = 0.8

prob of S2 = 0.6

prob of S3 = 0.5

what is the probability of getting from point A to B

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