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Exam 3-ISDS 2001 questions well answered to pass
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Exam 3-ISDS 2001 questions well answered to pass
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Exam 3-ISDS 2001If the null hypothesis is rejected by the goodness-of-fit test, the alternative hypothesis specifies which of
the population proportions differ from their hypothesized values - correct answer ✔✔FALSE
For a chi-square test of a contingency table, the expected frequencies for each cell are calculated
assuming the two events are independent of one another. - correct answer ✔✔TRUE
For a chi-square test of a contingency table, each expected frequency must be at least 3. - correct
answer ✔✔FALSE
A goodness-of-fit test analyzes for two qualitative variables whereas a chi-square test of a contingency
table is for a single qualitative variable. - correct answer ✔✔FALSE
For the Jarque-Bera test for normality, the test statistic is assumed to have a chi-square distribution with
two degrees of freedom. - correct answer ✔✔TRUE
For the goodness-of-fit test, the expected category frequencies are found using the ________.
A) sample proportions
B) proportions specified under the null hypothesis
C) average of the hypothesized and sample proportions
D) proportions specified under the alternative hypothesis - correct answer ✔✔proportions specified
under the null hypothesis
Which of the following null hypotheses is used to test if five population proportions are the same?
A) H0: p1 = p2 = p3 = p4 = p5 = 0.25
B) H0: p1 = p2 = p3 = p4 = 0.25
C) H0: p1 = p2 = p3 = p4 = 0.20
D) H0: p1 = p2 = p3 = p4 = p5 = 0.20 - correct answer ✔✔H0: p1 = p2 = p3 = p4 = p5 = 0.20
, For the goodness-of-fit test, the sum of the expected frequencies must equal _____
A) 1
B) n
C) k
D) k−1 - correct answer ✔✔n
The chi-square test of a contingency table is a test of independence for ________.
A) a single qualitative variable
B) two qualitative variables
C) two quantitative variables
D) three or more quantitative variables - correct answer ✔✔a single qualitative variable
For the chi-square test of a contingency table, the expected cell frequencies are found as ________.
A) the row total multiplied by the column total divided by the sample size
B) the observed cell frequency
C) (r−1)(c−1)
D) rc - correct answer ✔✔the row total multiplied by the column total divided by the sample size
The chi-square test of a contingency table is valid when the expected cell frequencies are ________.
A) equal to 0
B) more than 0 but less than 5
C) at least 5
D) negative - correct answer ✔✔at least 5
For the chi-square test of a contingency table, the expected cell frequencies are found as eij = (row i
total)/(column j total)/(sample size) which is the same as ________.
A) the observed cell frequencies
B) the cell probability multiplied by the sample size
C) the row total
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