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Solution Manual for Modern Physics with Modern Computational Methods: for Scientists and Engineers 3rd Edition by John Morrison, ISBN: 9780128177907, All 15 Chapters Covered, Verified Latest $14.99   Add to cart
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Solution Manual for Modern Physics with Modern Computational Methods: for Scientists and Engineers 3rd Edition by John Morrison, ISBN: 9780128177907, All 15 Chapters Covered, Verified Latest
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Solution Manual for Modern Physics with Modern Computational Methods: for Scientists and Engineers 3rd Edition by John Morrison, ISBN: 9780128177907, All 15 Chapters Covered, Verified Latest Edition Solution Manual for Modern Physics with Modern Computational Methods: for Scientists and Engineers 3...

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  • October 12, 2024
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  • modern physics with modern computational method
  • solution manual for modern physics with modern com
  • modern physics with modern computational methods
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SOLUTION MANUAL Modern Physics with Modern
Computational Methods: for Scientists and
Engineers 3rd Edition by Morrison Chapters 1- 15

,Table of contents
Z Z



1.ZTheZWave-ParticleZDuality

2.ZTheZSchrödingerZWaveZEquation

3.ZOperatorsZandZWaves

4.ZTheZHydrogenZAtom

5.ZMany-ElectronZAtoms

6.ZTheZEmergenceZofZMasersZandZLasers

7.ZDiatomicZMolecules

8.ZStatisticalZPhysics

9.ZElectronicZStructureZofZSolids

10.ZChargeZCarriersZinZSemiconductors

11.ZSemiconductorZLasers

12.ZTheZSpecialZTheoryZofZRelativity

13.ZTheZRelativisticZWaveZEquationsZandZGeneralZRelativity

14.ZParticleZPhysics

15.ZNuclearZPhysics

,1

TheZ Wave-ParticleZ DualityZ -Z Solutions




1. TheZenergyZofZphotonsZinZtermsZofZtheZwavelengthZofZlight
ZisZgivenZbyZEq.Z(1.5).ZFollowingZExampleZ 1.1ZandZsubstituti
ngZλZ=Z200ZeVZgives:
hc 1240Z eVZ ·Znm
= =Z6.2ZeV
EphotonZ= λ 200Znm
2. TheZ energyZ ofZ theZ beamZ eachZ secondZ is:
power 100Z W
= =Z100ZJ
EtotalZ= time 1Z s
TheZnumberZofZphotonsZcomesZfromZtheZtotalZenergyZdividedZ
byZtheZenergyZofZeachZphotonZ(seeZProblemZ1).ZTheZphoton’sZ
energyZmustZbeZconvertedZtoZJoulesZusingZtheZconstantZ1.602
Z×Z10−19ZJ/eVZ,ZseeZExampleZ1.5.ZTheZresultZis:

ZEtotalZ
N = = 100ZJ =Z1.01Z×Z1020
photons E
pho
ton 9.93Z×Z10−19
forZ theZ numberZ ofZ photonsZ strikingZ theZ surfaceZ eachZ second.
3.WeZareZgivenZtheZpowerZofZtheZlaserZinZmilliwatts,ZwhereZ1Z
mWZ=Z10−3ZWZ.ZTheZpowerZmayZbeZexpressedZas:Z1ZWZ=Z1ZJ
/s.ZFollowingZExampleZ1.1,ZtheZenergyZofZaZsingleZphotonZis
:
1240Z eVZ ·Znm
hcZ =Z1.960ZeV
EphotonZ = 632.8Z nm
Z =
λZ
WeZ nowZ convertZ toZ SIZ unitsZ (seeZ ExampleZ 1.5):
1.960ZeVZ×Z1.602Z×Z10−19ZJ/eVZ =Z3.14Z×Z10−19ZJ
FollowingZ theZsameZ procedureZ asZProblemZ 2:
1Z×Z10−3ZJ/s 15Z photons
RateZofZ emissionZ=Z = Z3.19Z×Z10
3.14Z×Z10−19Z J/photonZ s

, 2

4. TheZmaximumZkineticZenergyZofZphotoelectronsZisZfoundZu
singZEq.Z(1.6)ZandZtheZworkZfunctions,ZW,ZofZtheZmetalsZareZ
givenZinZTableZ1.1.ZFollowingZProblemZ 1,Z EphotonZ=Zhc/λZ=Z6.
20Z eVZ.Z ForZ partZ (a),Z NaZ hasZ WZ =Z2.28Z eVZ:
(KE)maxZ=Z6.20ZeVZ−Z2.28ZeVZ =Z3.92ZeV
Similarly,Z forZ AlZ metalZ inZ partZ (b),Z WZ =Z4.08Z eVZ givingZ(KE)maxZ=Z2.12
Z eV

andZforZAgZmetalZinZpartZ(c),ZWZ =Z4.73ZeVZ,ZgivingZ(KE)maxZ=Z1.47ZeVZ.

5.ThisZproblemZagainZconcernsZtheZphotoelectricZeffect.ZAsZinZP
roblemZ4,ZweZuseZEq.Z(1.6):
hcZ−Z
(KE)maxZ =
WZλ
whereZ WZ isZ theZ workZ functionZ ofZ theZ materialZ andZ theZ termZ hc/
λZ describesZtheZenergyZofZtheZincomingZphotons.ZSolvingZforZtheZl
atter:
hc
=Z(KE)maxZ+ZWZ =Z2.3ZeVZ +Z0.9Z eVZ =Z3.2Z eV
λZ
SolvingZ Eq.Z (1.5)Z forZ theZ wavelength:
1240Z eVZ ·Znm
λZ= =Z387.5Znm
3.2Z e
V
6. AZpotentialZenergyZofZ0.72ZeVZisZneededZtoZstopZtheZflowZofZelect
rons.ZHence,Z(KE)maxZofZtheZphotoelectronsZcanZbeZnoZmoreZtha
nZ0.72ZeV.ZSolvingZEq.Z(1.6)ZforZtheZworkZfunction:
hc 1240Z eVZ ·Z —Z0.72Z eVZ =Z1.98Z eV
W Z =Z —
λ nm
(KE)max
Z =
460Znm
7. ReversingZ theZ procedureZ fromZ ProblemZ 6,Z weZ startZ withZ Eq.Z (1.6):
hcZ 1240Z eVZ ·Z
(KE)maxZ = −ZWZ —Z1.98Z eVZ =Z3.19Z eV
= nm
λ
240Znm
Hence,ZaZstoppingZpotentialZofZ3.19ZeVZprohibitsZtheZelectronsZfr
omZreachingZtheZanode.

8. JustZ atZ threshold,Z theZ kineticZ energyZ ofZ theZ electronZ isZ
zero.Z SettingZ(KE)maxZ=Z0Z inZ Eq.Z (1.6),
hc
WZ= = 1240Z eVZ ·Z =Z3.44Z eV
λ0 nm

360Znm

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