BANA 3363 EXAM 3 WITH COMPLETE SOLUTIONS
A chi-squared distribution is symmetric. - Answer-false
The number of degrees of freedom for a contingency table with r rows and c columns is:
- Answer-( r - 1)( c - 1)
To determine the critical values in the chi-squared distribution table, you nee...
BANA 3363 EXAM 3 WITH COMPLETE
SOLUTIONS
A chi-squared distribution is symmetric. - Answer-false
The number of degrees of freedom for a contingency table with r rows and c columns is:
- Answer-( r - 1)( c - 1)
To determine the critical values in the chi-squared distribution table, you need to know
the: - Answer-degrees of freedom.
The only way the chi-squared test statistic can be zero is if the observed frequencies
are all exactly the same as the expected frequencies. - Answer-True
Which of the following conditions indicate that H 0 should be rejected in a goodness-of-
fit test? - Answer-The test statistic is large.
A large chi-squared test statistic in a test of a contingency table means you conclude: -
Answer-The two nominal variables are dependent.
In a test of a contingency table, rejecting the null hypothesis concludes the variables are
not independent. - Answer-True
The sampling distribution of the test statistic for a goodness-of-fit test with k categories
is a: - Answer-chi-squared distribution with k − 1 degrees of freedom.
A large chi-squared test statistic in a test of a contingency table means you conclude: -
Answer-The two nominal variables are dependent.
All of the expected frequencies in a chi-squared goodness-of-fit test must be equal to
each other. - Answer-False
A chi-squared goodness-of-fit test is always a two-tailed test. - Answer-False
The number of degrees of freedom for a contingency table with 4 rows and 8 columns is
- Answer-21
The chi-squared test of a contingency table is based upon: - Answer-two categorical
variables.
In a goodness-of-fit test, H 0 lists specific values for proportions and the test of a
contingency table does not. - Answer-True
A small chi-squared test statistic in a goodness-of-fit test supports the null hypothesis. -
Answer-True
, To address whether two variables are related in a contingency table, the null
hypothesis, H0, says that - Answer-The two variables are independent.
A chi-squared test is used to describe a population of categorical data. - Answer-True
A chi-squared test of a contingency table that results in a test statistic equal to zero
means: - Answer-The two nominal variables are independent.
The chi-squared test of a contingency table is based upon: - Answer-two categorical
variables.
A chi-squared test of a contingency table is applied to a contingency table with 4 rows
and 4 columns for two categorical variables. The degrees of freedom for this test must
be 9 - Answer-TRUE
The sampling distribution of the test statistic for a goodness-of-fit test with k categories
is a: - Answer-chi-squared distribution with k - 1 degrees of freedom
The analysis of variance (ANOVA) tests hypotheses about population variances and
requires all the population means to be equal. - Answer-False
The numerator and denominator degrees of freedom for the F-test in a one-way ANOVA
are, respectively, - Answer-( k - 1) and ( n - k)
In ANOVA, the variable that is used to separate the data into samples is called the
factor. - Answer-True
If the numerator (MSTR) degrees of freedom is 3 and the denominator (MSE) degrees
of freedom is 18, the total number of observations must equal 21. - Answer-False
In the one-way ANOVA where k is the number of treatments and n is the number of
observations in all samples, the number of degrees of freedom for error is: - Answer-n -
k
In one-way ANOVA, the test statistic is defined as the ratio of the mean square for error
(MSE) and the mean square for treatments (MSTR), namely, F = MSE / MSTR. -
Answer-False
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