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Exam (elaborations)

Math 110 Exam 3Questions With Complete Solutions

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  • Course
  • Math 110
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  • Math 110

perimeter and area of a square, rectangle, triangle, trapezoid, and circle - ANSWER- Surface area and volume of boxes, cans, cones, pyramids, and spheres - ANSWER- Pythagoras theorem - ANSWER-a² + b² = c² Fractals - ANSWER-Geometric shape that can be separated into parts, each of which ...

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  • October 2, 2024
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  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • Math 110
  • Math 110
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Math 110 Exam 3📏📐✏Questions With
Complete Solutions


perimeter and area of a square, rectangle, triangle, trapezoid, and circle - ANSWER-

Surface area and volume of boxes, cans, cones, pyramids, and spheres - ANSWER-

Pythagoras theorem - ANSWER-a² + b² = c²

Fractals - ANSWER-Geometric shape that can be separated into parts, each of which is
a reduced-scale version of the whole

Length and area of next step - ANSWER-

Graph - ANSWER-Diagram consisting of vertices and edges

Nodes or vertices - ANSWER-Points on the graph

Edges - ANSWER-Lines connecting the points

Loops - ANSWER-Edge with both ends the same point

Parallels - ANSWER-Two or more edges with the same two end points

Degrees - ANSWER-Number of times a path is in a starting location of an Euler Circuit
or path

Simple graph - ANSWER-A graph with no loops and no parallels

Eulers theorems - ANSWER-- A connected graph with all even vertices has at least one
Euler Circuit
- A connected graph with exactly two odd vertices (any number of even vertices) has at
least one Euler Trail. These trails start and end at each of the odd vertices
- It is not possible for any graph to have one odd vertex
- A graph with more than two odd vertices does mot have an Euler Trail or Circuit

Euler vs. Hamilton graphs - ANSWER-

Nearest neighbor algorithm - ANSWER-The nearest neighbour algorithm was one of the
first algorithms used to determine a solution to the travelling salesman problem. In it, the
salesman starts at a random city and repeatedly visits the nearest city until all have
been visited. It quickly yields a short tour, but usually not the optimal one.

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