ALGEBRA 2 GLENCOE MCGRAW LATEST 2024 EXAM TEST BANK QUESTIONS WITH 100% CORRECT DETAILED ANSWERS
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ALGEBRA 2 GLENCOE MCGRAW
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ALGEBRA 2 GLENCOE MCGRAW
ALGEBRA 2 GLENCOE MCGRAW LATEST 2024 EXAM TEST BANK QUESTIONS WITH 100% CORRECT DETAILED ANSWERS
system of equations - Answer-two or more equations with the same variables; to solve a system of equations with two variables, find the ordered pair that satisfies all of the equations
break even...
ALGEBRA 2 GLENCOE MCGRAW
LATEST 2024 EXAM TEST BANK
QUESTIONS WITH 100%
CORRECT DETAILED ANSWERS
system of equations - Answer-two or more equations with the same variables; to solve a
system of equations with two variables, find the ordered pair that satisfies all of the
equations
break even point - Answer-systems of equations are used by businesses to determine
the break-even point which is the point at which the income equals the cost
consistent - Answer-the system of equations that has at least one solution
inconsistent - Answer-the system of equations that has no solution
independent - Answer-the system of equations with exactly one solution
dependent - Answer-the system of equations with an infinite number of solutions
Substitution method - Answer-Algebraic method: (1) solve one equation for one of the
variables (2) substitute the resulting expression into the other equation to replace the
variable, then solve the equation. (3) substitute to solve for the other variable
elimination method - Answer-Algebraic method: (1) Multiply one or both equations by a
number to result in two equations that contain opposite terms (2) Add the equations,
eliminating one variable. Then solve the equation (3) Substitute to solve fore the other
variable
System of inequalities - Answer-Solving, means finding the ordered pairs that satisfy all
of the inequalities of the system: (1) Graph each inequality, shading the correct area (2)
Identify the region that is shaded for all of the inequalities. This is the solution.
Constraints - Answer-limitations
Linear programming - Answer-a method for finding maximum or minimum values of a
function over a given system of inequalities with each inequality representing a
constraint
, Feasible region - Answer-The vertices of the solution set that are substituted into the
function
bounded - Answer-The feasible region is enclosed by the constraints
unbounded - Answer-The feasible region is open and can go on forever
ordered triple - Answer-Systems in three variables that can have one solution, infinite
solutions or no solution
matrix - Answer-a rectangular array of variables or constants in horizontal rows and
vertical columns, usually enclosed in brackets. The numbers or data are organized so
that each position in the matrix has a purpose
element - Answer-each value in the matrix
preimage - Answer-the graph of an object before a transformation
image - Answer-the graph of an object after a transformation
rotation - Answer-a transformation in which an object is moved around a center point
usually the origin
Diagonal rule - Answer-(1) rewrite the 1st 2 columns to the right of the determinant
(2) draw diagonals, beginning with the upper left hand element. Multiply the elements in
each diagonal. Repeat the process, beginning with the upper right-hand element.
(3)Find the sum of the products of the elements in each set of diagonals (4)Subtract the
second sum from the first sum
Cramer's rule - Answer-Let C be the coefficient matrix of the system
ax + by = m a b
fx + gy = n f g
The solution of this system is x =
matrix equation - Answer-Using matrices to represent and solve systems of equations.
Write the left side of the matrix equation as the product of the coefficient matrix and the
variable matrix. Write the right side as a constant matrix.
variable matrix - Answer-only the variables of a system
constant matrix - Answer-only the constants of a system
zero - Answer-the x-intercept of the graph of a function; the points for which f(x)=0
vertex - Answer-where the axis of symmetry and the parabola meet
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