16 ounces correct answers1 pound
8 pints correct answers1 gallon
4 quarts correct answers1 gallon
2000 lbs correct answers1 ton
Supplemental angle correct answersadds up to 180 degrees
Complementary angle correct answersadds up to 90 degrees
If 3 times x exceeds 1/3 of y by 9, whi...
Supplemental angle correct answersadds up to 180 degrees
Complementary angle correct answersadds up to 90 degrees
If 3 times x exceeds 1/3 of y by 9, which of the following is the equation that shows the relationship
between x and y? correct answers3x-1/3*y=9
Questions about how fast people can do a job together?If the first painter can do the entire job in twelve
hours and the second painter can do it in eight hours, then (this here is the trick!) the first guy can do
1/12 of the job per hour, and the second guy can do 1/8 per hour. How much then can they do per hour
if they work together? correct answersTake each number of hours and use 1/x amount of hours.
Example: To find out how much they can do together per hour, I add together what they can do
individually per hour: 1/12 + 1/8 = 5/24.They can do 5/24 of the job per hour. Now I'll let "t" stand for
how long they take to do the job together. Then they can do 1/t per hour, so 5/24 = 1/t. Flip the
equation, and you get that t = 24/5 = 4.8 hours.
1/12 + 1/8 = 1/t
5/24 = 1/t
, 24/5 = t
=4.8 hours
One pipe can fill a pool 1.25 times faster than a second pipe. When both pipes are opened, they fill the
pool in five hours. How long would it take to fill the pool if only the slower pipe is used? correct
answershours to complete job:
fast pipe: f
slow pipe: 1.25f
together: 5
completed per hour:
fast pipe: 1/f
slow pipe: 1/1.25f
together: 1/5
adding their labor:
1/f + 1/1.25f = 1/5
multiplying through by 5f:
5 + 5/1.25 = f
5+4=f=9
Then 1.25f = 11.25, so the slower pipe takes 11.25 hours.
How much pure acid must be added to 12 ounces of a 40% acid solution in order to produce a 60% acid
solution? correct answersP1*V1 + P2*V2 = P3*V3
P1*V1 would be X*1
P2*V2 is volume of first*percentage of first
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