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Exam (elaborations)

AC Circuits Test 1 Questions with Revised and Updated answers

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AC Circuits Test 1 Questions with Revised and Updated answers Average Power in an AC circuit - Answer-Voltage squarred divided by Resitance (P = V²÷R) (P = I²×R) Capacitive Reactance - Answer-1 divided by 2 pie frequency capacitance (Xc = 1 ÷ 2πƒC) Inductive Reactance - Answer-2 p...

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  • September 9, 2024
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  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • ac circuits
  • AC Circuits
  • AC Circuits
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AC Circuits Test 1 Questions with
Revised and Updated answers

Average Power in an AC circuit - Answer-Voltage squarred divided by Resitance
(P = V²÷R)
(P = I²×R)

Capacitive Reactance - Answer-1 divided by 2 pie frequency capacitance
(Xc = 1 ÷ 2πƒC)

Inductive Reactance - Answer-2 pie frequency L
(XL = 2πƒL)

Ohm's law Resistor - Answer-Velocity divided by Current
(R = V÷I)

Ohm's law Capacitor - Answer-Voltage divided by Current
(Xc = V÷I)

Ohm's law Inductor - Answer-Voltage divided by Current
(XL = V÷I)

Ohm's law Generalized to AC circuits - Answer-Ohm's law Generalized to AC circuits

Impedance for a series RLC circuit - Answer-Square Root of paranthesis Restitance
squared + paranthesis Inductive Reactance - Capacitive Reactance end paranthesis
squared
(Z=√(R²+ (XL-Xc)²)

Phase angle between voltage and current in a series RLC circuit - Answer-Tangent
Theta = Inductive Reactance - Capacitive Reactance divided by Resistance

Power factor for an RLC circuit - Answer-Cosine Theta = Resitance divided by
Impedance

Average power in terms of power factor - Answer-Current RMS Voltage RMS Cosine
Theta

Resonance frequency of a series RLC circuit - Answer-1 over 2 pie Square Root L
Current
Instantaneous (AC)

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