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26401 Load Calculations - Feeders and Services Exam Questions and Complete Solutions Graded A+
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26401 Load Calculations - Feeders and Services Exam Questions and Complete Solutions Graded A+
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26401 Load Calculations- Feeders and Services
Exam Questions and
Complete Solutions
Graded A+
Denning [Date] [Course title]
, Load calculated at 2 circuit 1500VA. - Answer: Small Appliance Ciruit
Voltage drop formula 1
VD = (2*L*R*I)/1,000 - Answer: VD = voltage drop (in volts)
L = load center or total length in feet
R = conductor resistance per NEC Chapter 9, Table 8
I = current
The number 1,000 represents 1,000' or less of conductor.
Show window loads should be calculated at _____ per linear foot of show window. - Answer: 200VA
What is the minimum demand required for the portion of a feeder that supplies 30' of show windows?
6,000 VA
5,400 VA
3,000 VA
2,700 VA - Answer: ft x va = va
30ft x 200VA = 6,000VA
NEC 220.14(C)(2)
At 200 Volt-amperes per linear 300 mm (1 ft) of show window
Voltage drop formula 2
VD = (2*L*K*I)/CM - Answer: VD = voltage drop
L = load center or total length in feet
K= constant (12.9 for copper conductors; 21.2 for aluminum conductors)
I = current
CM= area of the conductor in circular mils (from NEC Chapter 9, Table 8)
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