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MATH302 Quiz 5 | Questions and Answers Latest {} A+ Graded | 100% Verified

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MATH302 Quiz 5 | Questions and Answers Latest {} A+ Graded | 100% Verified

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MATH302 Quiz 5 | Questions and Answers Latest {2024- 2025} A+ Graded | 100% Verified




Select the correct answer for the blank: If everything else stays the same, the required sample size ____
as the confidence level increases to reach the same margin of error. - Increases



A random sample of college basketball players had an average height of 66.35 inches. Based on this
sample, (65.6, 67.1) found to be a 94% confidence interval for the population mean height of college
basketball players. Select the correct answer to interpret this interval. - We are 94% confident that the
population mean height of college basketball players is between 65.6 and 67.1 inches.



The population standard deviation for the height of college basketball players is 3.4 inches. If we want to
estimate 95% confidence interval for the population mean height of these players with a 0.5 margin of
error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole
number) - a = (1-.95) = 0.05 = (0.05/2) = 0.025 = (1-0.025) = 0.975



Z-Critical Value = NORM.S.INV(0.975) = 1.96



SD = 3.4



ME = 0.5



n = (SD^2∗Z^2)/ME^2



n = (3.42^2∗1.96^2)/.5^2



n = 177.635584 = 178



There is no prior information about the proportion of Americans who support gun control in 2018. If we
want to estimate 92% confidence interval for the true proportion of Americans who support gun control
in 2018 with a 0.2 margin of error, how many randomly selected Americans must be surveyed? (Round
up your answer to nearest whole number) - a = (1-.92) = 0.08 = (0.08/2) = 0.04 = (1-0.04) = .96

, Z-Critical Value =NORM.S.INV(.96) = 1.750686



ME = 0.2



n = (p*q*Z^2)/ME^2



n = (0.5*0.5*1.750686^2)/0.2^2



N = 20



The population standard deviation for the height of college hockey players is 3.4 inches. If we want to
estimate 90% confidence interval for the population mean height of these players with a 0.6 margin of
error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole
number) - a = (1-.90) = 0.1 = (0.1/2) = 0.05 = (1-0.05) = 0.95



Z-Critical Value = NORM.SINV(.95) = 1.645



SD = 3.4



ME = 0.6



n = (SD^2∗Z^2)/ME^2



n = (3.42^2∗1.645^2)/0.6^2



n = 86.8934694 = 87



The population standard deviation for the height of college baseball players is 3.2 inches. If we want to
estimate 90% confidence interval for the population mean height of these players with a 0.7 margin of
error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole
number) - a = (1-.90) = 0.1 = (0.1/2) = 0.05 = (1-0.05) = 0.95

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