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C to MIPS Actual Full Exam Questions With Correct Answers Success Guaranteed..
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arithmetic expression int f, g, h, i, j; $s0 (g + h) - (i + j) f = (g + h) - (i + j); $s1 i + j - correct answer MIPS add $s0, $s1, $s2 # $s0 = g + h add $s1, $s3, $s4 # $s1 = i + j sub $s0, $s0, $s1 # f = (g + h) - (i + j) simple if stateme...

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  • August 22, 2024
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  • 2024/2025
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C to MIPS

arithmetic expression



int f, g, h, i, j; $s0 (g + h) - (i + j)

f = (g + h) - (i + j); $s1 i + j - correct answer MIPS



add $s0, $s1, $s2 # $s0 = g + h

add $s1, $s3, $s4 # $s1 = i + j

sub $s0, $s0, $s1 # f = (g + h) - (i + j)



simple if statement:

if ( i == j ) $s1 i

i++ ; $s2 j

j-- ; - correct answer assuming $s1 stores i and $s2 stores j:

bne $s1, $s2, L1 # branch if !( i == j )

addi $s1, $s1, 1 # i++

L1: addi $s2, $s2, -1 # j--



Conditional: if-else:



if ( i == j ) $s1 i

i++ ; $s2 j

else

j-- ;

j += i ; - correct answer Once we've done the if-body, we need to jump over
the else-body

bne $s1, $s2, ELSE # branch if !( i == j )

, addi $s1, $s1, 1 # i++

j NEXT # jump over else

ELSE: addi $s2, $s2, -1 # else j--

NEXT: add $s2, $s2, $s1 # j += i



Conditional: compound condition with AND:



if ( i == j && i == k ) // if ( <cond1> && <cond2> )

i++ ; // if body

else $s1 i

j-- ; // else body $s2 j

j = i + k ; $s3 k - correct answer bne $s1, $s2, ELSE # cond1: branch if !( i == j )

bne $s1, $s3, ELSE # cond2: branch if !( i == k )

addi $s1, $s1, 1 # if-body: i++

j NEXT # jump over else

ELSE: addi $s2, $s2, -1 # else-body: j--

NEXT: add $s2, $s1, $s3 # j = i + k



Conditional: compound condition with OR:



if ( <cond1> || <cond2> )

i++ ; // if-body $s1 i

else $s2 j

j-- ; // else-body $s3 k

j = i + k ; - correct answer beq $s1, $s2, IF # cond1: branch if ( i == j )

# Notice branch on TRUE

bne $s1, $s3, ELSE # cond2: branch if ! ( i == k )

IF: addi $s1, $s1, 1 # if-body: i++

j NEXT # jump over else

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