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BIO B182 BEXAM B2 NEWLY UPDATED QUESTIONS WITH CORRECT ANSWERS ALREADY GRADED A+ $13.99   Add to cart

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BIO B182 BEXAM B2 NEWLY UPDATED QUESTIONS WITH CORRECT ANSWERS ALREADY GRADED A+

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  • BIO 182

BIO B182 BEXAM B2 NEWLY UPDATED QUESTIONS WITH CORRECT ANSWERS ALREADY GRADED A+

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  • August 13, 2024
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  • 2024/2025
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  • BIO 182
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BIO 182 EXAM 2 NEWLY UPDATED QUESTIONS WITH CORRECT ANSWERS
B B B




ALREADY GRADED A+




1. How many modes of selection are there?: 3
bb bb bb bb bb bb bb




2. What are the modes of selection?: Stabilizing selection, directional selection,
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bb and disruptive selection
bb bb
ime but bb




3. Stabilizing Selection: The mean of the trait remains similar over t
bb bb bb bb bb bb bb bb bb bb




bb standard deviation decreases
bb bb




4. Directional Selection: The mean phenotype shifts in a particular directio
bb bb bb bb bb bb bb bb




5. Disruptive Selection: The standard deviation of the trait increases as
bb bb bb bb bb bb bb bb



individuals bb




with the mean value disappear.
bb bb bb bb bb




6. Stabilizing Selection Explained: The stronger the selective pressure against
bb bb bb bb bb bb bb bb




bb extreme phenotypes, the narrower the distribution of phenotypes will be in
bb bb bb bb bb bb bb bb bb bb




1 bb/

,bb future generations. In the end, the size of the standard deviation will reflect both
bb bb bb bb bb bb bb bb bb bb bb bb bb




bb the strength of selection against extremes and the frequency of mutations creating
bb bb bb bb bb bb bb bb bb bb bb




bb new variation. Thus, when we observe a wide range of phenotypes in a
bb bb bb bb bb bb bb bb bb bb bb bb




bb population, we might infer weak selective pressure against the extremes.
bb bb bb bb bb bb bb bb bb




7. Directional Selection Explained: The population's environment changes. The
bb bb bb bb bb bb bb




bb mean phenotype in the population may no longer be the phenotype that reproduces
bb bb bb bb bb bb bb bb bb bb bb bb




bb the most. Over time, we should expect the mean phenotype to shift higher or
bb bb bb bb bb bb bb bb bb bb bb bb bb




bb lower, depending on the direction of selective pressure. Once the mean phenotype
bb bb bb bb bb bb bb bb bb bb bb




bb catches up to the change in the environment, stabilizing selection will resume.
bb bb bb bb bb bb bb bb bb bb bb




The environment must change slowly enough for the population to persist. If the
bb bb bb bb bb bb bb bb bb bb bb bb




bb environment changes too quickly, no members of the population will be able to
bb bb bb bb bb bb bb bb bb bb bb bb




bb reproduce, leading to extinction. bb bb bb




8. Disruptive Selection Explained: A population can occupy an environment in
bb bb bb bb bb bb bb bb bb




bb which individuals with extreme phenotypes reproduce more than individuals
bb bb bb bb bb bb bb bb




bb with the mean phenotype.
bb bb bb




This mode of selection occurs when several distinct strategies confer greater
bb bb bb bb bb bb bb bb bb bb




bb reproductive success than other strategies do. Can produce new species when
bb bb bb bb bb bb bb bb bb bb




bb individuals choose to mate only with similar-looking individuals. This non-random
bb bb bb bb bb bb bb bb bb




bb mating prevents recombination from restoring intermediate phenotypes.
bb bb bb bb bb bb




2 bb /

,9. Evolution by Natural Selection: Heritable variation leads to differential
bb bb bb bb bb bb bb bb




bb repro- ductive success
bb bb




10. Selection and Fitness:
bb bb




3 /
bb

, 11.Directional Selection Equation: y=bx+c bb bb bb




y=relative fitness bb




bb x= trait value
bb bb




b= strength of selection
bb bb bb




bb c=parameter

12.True or False? If the slope of the relationship between the phenotype
bb bb bb bb bb bb bb bb bb bb bb




bb and fitness is positive, natural selection would decrease the phenotype over
bb bb bb bb bb bb bb bb bb bb




bb generations.: False, it would increase the value of the trait over time
bb bb bb bb bb bb bb bb bb bb bb




13.Stabilizing Selection Equation: y=ax^2+bx+c bb bb bb




y=relative fitness bb




bb x= trait value
bb bb




a/b= strength of bb bb




bb selection c= parameter
bb bb




14.True or False? If the parameter for the squared term is negative,
bb bb bb bb bb bb bb bb bb bb bb




4 /
bb

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