Write a balanced half-reaction for the oxidation of manganese ion Mn2+ to solid
manganese dioxide MnO2 in basic aqueous solution. Be sure to add physical state
symbols where appropriate. - answerMn^2+(aq)+4OH^-(aq)=MnO2(s)+2H2O(l)+2e^-
Write a balanced half-reaction for the reduction of nitrate ion NO−3 to gaseous nitric
oxide NO in basic aqueous solution. Be sure to add physical state symbols where
appropriate. - answerNO3^-(aq)+2H2O(l)+3e^-=NO(g)+4OH^-(aq)
Write a balanced half-reaction for the oxidation of gaseous nitric oxide
NO
to aqueous nitrous acid
HNO2
in basic aqueous solution. Be sure to add physical state symbols where appropriate. -
answerNO(g)+OH^-(aq)=HNO2(aq)+e^-
Write a balanced half-reaction for the oxidation of solid iodine dioxide
IO2
to iodate ion
IO−3
in basic aqueous solution. Be sure to add physical state symbols where appropriate. -
answerIO2(s)+2OH^-(aq)=IO3^-(aq)+H2O(l)+e^-
Write a balanced half-reaction for the reduction of gaseous nitrogen
N2
to aqueous hydrazine
N2H4
in basic aqueous solution. Be sure to add physical state symbols where appropriate. -
answerN2(g)+4H2O(l)+4e^-=N2H4(aq)+4OH^-(aq)
Write a balanced half-reaction for the oxidation of gaseous arsine AsH3 to aqueous
arsenic acid H3AsO4 in basic aqueous solution. Be sure to add physical state symbols
where appropriate. - answerAsH3(g)+8OH^-(aq)=H3AsO4(aq)+ 4H2O(l)+8e^-
Write a balanced half-reaction for the reduction of permanganate ion MnO−4 to
manganese ion Mn2+ in basic aqueous solution. Be sure to add physical state symbols
where appropriate. - answerMnO4^-(aq)+4H2O(l)+5e^-=Mn^2+(aq)+8OH^-(aq)
, Write a balanced half-reaction for the reduction of gaseous oxygen O2 to liquid water
H2O in basic aqueous solution. Be sure to add physical state symbols where
appropriate. - answerO2(g)+2H2O(l)+4e^-=4OH^-(aq)
Write a balanced half-reaction for the oxidation of aqueous hydrogen peroxide
H2O2
to gaseous oxygen
O2
in basic aqueous solution. Be sure to add physical state symbols where appropriate. -
answerH2O2(aq)+2OH^-(aq)=O2(g)+2H2O(l)+
2e^-
Write a balanced half-reaction for the reduction of aqueous hydrogen peroxide H2O2 to
liquid water H2O in basic aqueous solution. Be sure to add physical state symbols
where appropriate. - answerH2O2(aq)+2e^-=2OH^-(aq)
Write a balanced half-reaction for the oxidation of chromium ion
Cr3+
to dichromate ion
Cr2O2−7
in basic aqueous solution. Be sure to add physical state symbols where appropriate. -
answer2Cr^+(aq)+14OH^-(aq)=CrO7^2-(aq)+7H2O(l)+6e^-
Write a balanced half-reaction for the reduction of nitrate ion
NO−3
to gaseous nitrogen dioxide
NO2
in basic aqueous solution. Be sure to add physical state symbols where appropriate. -
answerNO3^-(aq)+H2O(l)+e^-=NO2(g)+2OH^-(aq)
Write a balanced half-reaction for the oxidation of solid manganese dioxide
MnO2
to permanganate ion
MnO−4
in basic aqueous solution. Be sure to add physical state symbols where appropriate. -
answerMnO2(s)+4OH^-(aq)=MnO4^-(aq)+2H2O(l)+3e^-
Write a balanced half-reaction for the reduction of aqueous nitrous acid
HNO2
to gaseous nitric oxide
NO
in basic aqueous solution. Be sure to add physical state symbols where appropriate. -
answerHNO2(aq)+e^-=NO(g)+OH^-(aq)
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying these notes from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller jw638729. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy these notes for $15.99. You're not tied to anything after your purchase.