,Solution and Answer Guide: Stewart Kokoska, Calculus: Concepts and Contexts, 5e, 2024, 9780357632499, Chapter 2: Section Concept Check
CALCULUS CONCEPTS AND CONTEXTS 5TH EDITION
BY JAMES STEWART, KOKOSKA (CHAPTER 1_13)
SOLUTIONS MANUAL
Chapter 1-13
CHAPTER 1: SECTION 1.1
TABLE OF CONTENTS
End of Section Exercise Solutions ............................................................................................................. 1
END OF SECTION EXERCISE SOLUTIONS
1.1.1
(a) f (1) 3
(b) f (1) 0.2
(c) f (x) 1 when x = 0 and x = 3.
(d) f (x) 0 when x ≈ –0.8.
(e) The domain of f is 2 x 4. The range of f is 1 y 3.
(f) f is increasing on the interval2 x 1.
1.1.2
(a) f (4) 2; g(3) 4
(b) f (x) g(x) when x = –2 and x = 2.
(c) f (x) 1 when x ≈ –3.4.
(d) f is decreasing on the interval 0 x 4.
(e) The domain of f is 4 x 4. The range of f is 2 y 3.
(f) The domain of g is 4 x 4. The range of g is 0.5 y 4.
, Solution and Answer Guide: Stewart Kokoska, Calculus: Concepts and Contexts, 5e, 2024, 9780357632499, Chapter 2: Section Concept Check
1.1.10
The domain of f (t) 3 2t 1 is all real numbers.
1.1.11
g t 3 t 2 t is defined when 3 t 0 t 3 and 2 t 0 t 2. Thus, the domain is t 2,
or , 2.
1.1.12
1
The domain of h(x) is , 0 5, .
4
x 5x
2
1.1.13
The domain of F( p) 2 p is0 p 4.
1.1.14
The domain of f (u) u 1 is u | u 2, 1.
1
1
u 1
1.1.15
(a) This function shifts the graph of y = |x| down two units and to the left one unit.
(b) This function shifts the graph of y = |x| down two units
(c) This function reflects the graph of y = |x| about the x-axis, shifts it up 3 units and then to the left 2
units.
(d) This function reflects the graph of y = |x| about the x-axis and then shifts it up 4 units.
(e) This function reflects the graph of y = |x| about the x-axis, shifts it up 2 units then four units to the
left.
(f) This function is a parabola that opens up with vertex at (0, 5). It is not a transformation of y = |x|.
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