Exam (elaborations)
CSE 2050 Exam 2
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Exam of 5 pages for the course Pulmonary Rosh at Pulmonary Rosh (CSE 2050 Exam 2)
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CSE 2050 Exam 2Average Running time of Hash Mapping for put and get - ANS-O(1)
Basic Methods of Mapping - ANS-get - returns the value of the key, if it exists
put - inserts the key with its value to the mapping
Benefit of Using Selection Sort - ANS-It only makes one swap per element (O(n)), which
can reduce memory cost
Best and Worse Case for Selection Sort - ANS-Best Case: reverse sorted, though
O(n^2), randomized sometimes
Worst Case: if just one object are out of places
Best and Worst Case for Bubble Sort - ANS-Best Case: if only one item (particularly the
rabbit) is unsorted, O(n)
Worst Case: O(n^2), has to go through every item (reversed sorted list, turtle,
randomized)
Best and Worst Case for Insertion Sort - ANS-Best Case: only one object out of place
O(n) swap
Worst Case: reversed sorted (O(n^2))
Best Case for Binary Search - ANS-O(1), if median happens to be the item
Binary Search - ANS-An ordered list is divided in 2 with each comparison.
Combine - ANS-Combines all the small solutions from each sub problems to a solution
for the big problem
Compare Insertion Sort vs Selection Sort (3) - ANS-1) Number of comparisons is less
than number of swaps in insertion
2) Insertion is generally more efficient
3) O(n) swaps in selection vs O(n^2) swaps in insertion
Conquer - ANS-Solve the sub problem recursively until a solution to the sub problem is
found
Divide - ANS-Splitting the big problem into subproblems
, Drawbacks of Recursion - ANS-Can be slow, take a lot of memory space, can solve the
same subproblems repeatedly
Dynamic Programming - ANS-Sub-problems are solved from the bottom up. Each
problem is trivially solved as the combination of previously-solved subproblems.
Greedy Algorithm - ANS-an algorithm that always tries the solution path that appears to
be the best.
Hash Collision - ANS-two (or more) keys hash to same slot
Hash function - ANS-Takes a key and return an integer, which can be used to define
what "bucket" it should go in
Hash Table - ANS-A table of information that is accessed by way of a shortened search
key (the hash value).
Invariant - ANS-something that holds true throughout the execution of a code
Invariant for Bubble Sort - ANS-The biggest items of the list are in their sorted, final
position after each loop
Invariant for Insertion Sort - ANS-After each loop, a small portion of the list, or sub list,
are sorted, but does not mean that each element are in their final position
Invariant for Selection Sort - ANS-Same thing with Bubble Sort, where the biggest items
of the list are in their sorted, final position after each loop
Mapping - ANS-is a collection of key-value pairs such that the keys are unique
Memoization - ANS-Before attempting to solve a new sub-problem, a collection is
referenced to see if this sub-problem has already been solved.
Merge Sort - ANS-Sorting algorithm that keeps splitting the list by halves until the list
has one item in it, which when recursively calls back up, it will compare each values
from each list and sort it until a final sorted list is produced
MergeSort vs QuickSort (3) - ANS-1) MergeSort requires more memory
2) MergeSort has a complicated divide step, QuickSort has a complicated conquer step
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