Neet aspirant practis paper for neet 2025 physics ,chemistry,bio.
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Course
Neet
Institution
The overall difficulty level of the exam was easy to moderate. While physics and Chemistry were a bit lengthy and easy to moderate as compared to last year's NEET UG exam
Test Pattern
(1701CMD305721018) *1701CMD305721018*
CLASSROOM CONTACT PROGRAMME
®
NEET(UG)
MINOR
17 - 04 - 2022
PRE-MEDICAL : ACHIEVER COURSE (PHASE-MAW)
44 This Booklet contains 44 pages.
Do not open this Test Booklet until you are asked to do so.
Read carefully the Instructions on the Back Cover of this Test Booklet.
: Important Instructions :
1. -1 -2 1. On the Answer Sheet, fill in the particulars on Side-1
and Side-2 carefully with blue/black ball point pen only.
2. 3 180 2. The test is of 3 hours duration and this Test Booklet
4 4 contains 180 questions. Each question carries 4 marks.
For each correct response, the candidate will get 4 marks.
For each incorrect response, one mark will be deducted
720 from the total scores. The maximum marks are 720.
3. 3. Use Blue/Black Ball Point Pen only for writing
particulars on this page/marking responses.
4. 4. Rough work is to be done on the space provided for this
purpose in the Test Booklet only.
5. 5. On completion of the test, the candidate must
hand over the Answer Sheet to the Invigilator
before leaving the Room/Hall. The candidates
are allowed to take away this Test Booklet with
them.
6. 6. The candidates should ensure that the Answer Sheet
is not folded. Do not make any stray marks on the
Answer Sheet. Do not write your Form No. anywhere
else except in the specified space in the Test Booklet/
Answer Sheet.
7. 7. Use of white fluid for correction is not permissible on
the Answer Sheet.
In case of any ambiguity in translation of any question, English version shall be treated as final.
( ):
Name of the Candidate (in Capitals)
:
Form Number : in figures
:
: in words
( ):
Centre of Examination (in Capitals) :
: :
Candidate’s Signature : Invigilator’s Signature :
Your Target is to secure Good Rank in Pre-Medical 2022
Minor / English/Hindi / 17042022 Page 1/44
, ACHIEVER COURSE (PHASE : MAW)
ALLEN MINOR TEST DATE : 17 - 04 - 2022
SYLLABUS
PHYSICS : Magnetism, Electrostatics, Capacitance, Circular Motion &
Rotational Motion
CHEMISTRY : p-Block, Co-ordination Compound, s-Block, d and f-Block,
Metallurgy, Chemical Equilibrium, Ionic Equilibrium up to
Solubility, GOC-II (NSR, ESR, Name Reaction, Elimination &
Biomolecules)
BIOLOGY : Earthworm, Plant Diversity (till taught), Principle of Inheritance
& Biotechnology
Minor / English/Hindi / 17042022 Page 2/44
,
1. The time period of a vibration magnetometer is T0. Its 1. T0
magnet is replaced by another magnet whose moment
of inertia is 3 times and magnetic moment is 1/3 of the 3 1/3
initial magnet. The time period now will be :- :-
(1) 3T0 (2) T0 (1) 3T0 (2) T0
(3) T (4) T0/3 (3) T (4) T0/3
2. A current carrying loop is placed in a uniform magnetic 2.
field in four different orientations, I, II, III & IV. I, II, III IV
Arrange them in the decreasing order of potential :-
energy :-
n II. B
I. B
n II. B
I. B n
n
n
n
III. B IV. B
III. B IV. B n
n
(1) I > III > II > IV (2) I > II > III > IV (1) I > III > II > IV (2) I > II > III > IV
(3) I > IV > II > III (4) III > IV > I > II (3) I > IV > II > III (4) III > IV > I > II
3. An alternating electric field, of frequency , is applied 3. ( = m)
across the dees (radius = R) of a cyclotron that is being (Ds) ( R)
used to accelerate protons (mass = m). The operating
magnetic field (B) used in the cyclotron and the kinetic
energy (K) of the proton beam, produced by it, are (B)
given by : (K) :
2 m 2 m
(1) B = and K = 2m22R2 (1) B = and K = 2m22R2
e e
m m
(2) B = and K = m2R2 (2) B = and K = m2R2
e e
m m
(3) B = and K = 2m22R2 (3) B = and K = 2m22R2
e e
2 m 2 m
(4) B = and K = m2R2 (4) B = and K = m2R2
e e
4. An iron rod of length L and magnetic moment M is 4. L M
bent in the form of a semicircle. Now its magnetic
:
moment will be :
2M M 2M M
(1) M (2) (3) (4) M (1) M (2) (3) (4) M
,
5. Five very long, straight wires are bound together to 5.
form a small cable. Currents carried by the wires are I 1 = 20A,
I1 = 20A, I2 = –6A, I3 = 12A, I4= –7A, I5 = 18A. The I2 = –6A, I3 = 12A, I4= –7A, I5 = 18A
magnetic induction at a distance of 10 cm from the 10 cm
cable is : (1) 34 µT (2) 74 mT
(1) 34 µT (2) 74 mT (3) 34 mT (4) 74µT (3) 34 mT (4) 74µT
6. An alpha particle revolves around a charge –Q with 6. – –Q ‘v’ ‘r’
speed ‘v’ on a circular orbit of radius ‘r’. Due to
its motion magnetic field produced at centre and
magnetic moment respectively are
0 ev evr 0 ev 0 ev evr 0 ev
(1) , (2) , evr (1) , (2) , evr
4r 2 4r 4r 2 4r
0 ev ev evr 0 ev 0 ev evr
(3) , evr (4) 0 2 , (3) , evr (4) ,
2r 2
4r 2 2r 2 4r 2 2
7. A magnetic dipole is placed at an angle 60° from the 7. 60°
direction of uniform magnetic fields. If it rotated
through additional angle 60° from its position against
60° :-
the action of torque, then work done is :-
MB MB MB MB
(1) MB (2) (3) (4) Zero (1) MB (2) (3) (4)
2 4 2 4
8. A particle of charge q and mass m moves in a circular 8. q m r
orbit of radius r with angular speed .The ratio of the
magnitude of its magnetic moment to that of its
:-
angular momentum depends on :-
(1) and q (2) , q and m (1) q (2) , q m
(3) q and m (4) and m (3) q m (4) m
9. A winding which is used to frame a solenoid can bear 9. 10 A
a maximum to 10 A current. If length of solenoid is 80cm
80cm and it's cross sectional radius is 3cm then 3 cm
required length of winding wire is : (B = 0.2 T) (B = 0.2 T)
(1) 1.2 × 102m (2) 4.8 × 102m (1) 1.2 × 102m (2) 4.8 × 102m
(3) 2.4 × 103m (4) 6 × 103m (3) 2.4 × 103m (4) 6 × 103m
10. A circular current carrying coil has a radius R. The 10. R
distance from the centre of the coil on the axis where
1 1
the magnetic induction will be th of its value at
8 8
the centre of the coil, is
R 2
(1) (2) R 3 (3) 2 3R (4) R
R 2 3 3
(1) (2) R 3 (3) 2 3R (4) R
3 3
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