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PORTAGE LEARNING CHEMISTRY CHEM 103 UNIT 2 EXAM QUESTIONS WITH COMPLETE SOLUTIONS VERIFIED $9.09   Add to cart

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PORTAGE LEARNING CHEMISTRY CHEM 103 UNIT 2 EXAM QUESTIONS WITH COMPLETE SOLUTIONS VERIFIED

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PORTAGE LEARNING CHEMISTRY CHEM 103 UNIT 2 EXAM QUESTIONS WITH COMPLETE SOLUTIONS VERIFIED 1. Ca3N2 Ca 3 x 40.08 = 120.24 N 2 x 14.01 = 28.02 120.24 + 28.02 = 148.26 2. Li3PO4 Li 3 x 6.941 = 20.823 P 1 x 30.97 = 30.97 O 4 x 16.00 = 64.00 20.823 + 30.97 + 64.00 = 115.793 3. NH4NO3...

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  • June 22, 2024
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PORTAGE LEARNING CHEMISTRY CHEM 103 UNIT 2 EXAM
QUESTIONS WITH COMPLETE SOLUTIONS VERIFIED


1. Ca3N2
Ca 3 x 40.08 = 120.24
N 2 x 14.01 = 28.02
120.24 + 28.02 = 148.26


2. Li3PO4
Li 3 x 6.941 = 20.823
P 1 x 30.97 = 30.97
O 4 x 16.00 = 64.00
20.823 + 30.97 + 64.00 = 115.793


3. NH4NO3
N 2 x 14.01 = 28.02
H 4 x 1.008 = 4.032
O 3 x 16.00 = 48.00
28.02 + 4.032 + 48.00 = 80.052
Number your answers, and show your work. Be sure to give answers with the correct
units.
Calculate the molecular weight of the following compounds:


1. Ca3N2 ____________________


2. Li3PO4 ____________________


3. NH4NO3 ____________________
1.

, MW of NH4NO3 = 80.052
moles = 10..052 = 0.125 mole
2.
MW of Li3PO4 = 115.793
grams = 0.0500 x 115.793 = 5.79 grams
Number your answers, and show your work. Be sure to give answers with the correct
units.


Calculate the number of moles in 10.0 grams in the following compound:


1. NH4NO3 ____________________


Calculate the number of grams of each in 0.0500 mol in the following compound:


2. Li3PO4 ____________________
1. MW of Na2SO4 = 2 (22.99) + (32.07) + 4(16.00) = 142.05
%Na = 45..05 x 100 = 32.37%
%S = 32..05 x 100 = 22.58%
%O = 64..05 x 100 = 45.05%
2. MW of Ca(NO3)2 = (40.08) + 2 (14.01) + 6 (16.00) = 164.1
%Ca = 40..1 x 100 = 24.42%
%N = 28..1 x 100 = 17.07%
%O = 96..1 x 100 = 58.50%
Calculate the percent of each element present in the following compounds:
1. Na2SO4
Na = __________ S = __________ O = __________
2. Ca(NO3)2
Ca = __________ N = __________ O = __________
1.) % Composition of a compound is:
52.56% Fe 52.56% Fe ÷ 55.85 = 0.941 (smallest number of the set)
2.83% H 2.83% H ÷ 1.008 = 2.808

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