Summary
Summary Assignment 1 Full Attempt 100% COS1501
- Course
- Institution
Full assignment 1 for cos1501 with 100%
[Show more]
Seller
Follow
drowsy-polls0j
Reviews received
Content preview
UNISA 2023 COS1501-23-Y Welcome Message Assessment 1QUIZ
COS1501 Assignment 1 Memo Review
Started on Tuesday, 2 May 2023, 6:42 PM
State Finished
Completed on Tuesday, 2 May 2023, 6:50 PM
Time taken 7 mins 57 secs
Marks 15.00/15.00
Grade 100.00 out of 100.00
Question 1 Which one of the following alternatives is FALSE regarding the number sets Z, Z+, Z≥, Q
Correct and R?
Mark 1.00 out of
1.00
a. Z≥ ⊆ Z
b. Z+ ⊆ Z≥
c. R ⊆ Q
d. Z+ ⊆ R
The different number sets are described in Chapter 1 and 2.
Z = {... -4, -3, -2, -1, 0, 1, 2, 3, 4, ...} Z≥ = {0, 1, 2, 3, 4, ...} Z+ = {1, 2, 3, 4, ...}
From the diagram below it is clear that all elements in Z+ is also in the set Z≥, and all
elements in Z≥ is also in the set Z etc.
We can therefore say that Z+⊆ Z≥ ⊆ Z ⊆ Q ⊆ R.
The correct answer is: R ⊆ Q
https://mymodules.dtls.unisa.ac.za/mod/quiz/review.php?attempt=10149394&cmid=618676 2023/10/31, 9 08 AM
Page 1 of 10
:
, Question 2 The set of all non-negative integers x less than 16 such that x2 is an even integer can
Correct be described as the set:
Mark 1.00 out of (Note: The required set must include as elements all non-negative integers x such
1.00 that all the requirements for the set are met.)
a. {x| x ∈ Z≥, x <
16, x2 = 2k The set {x | x Î Z≥, x < 16, x2 = 2k for some k Î Z} is the set
for some k ∈ of all non-negative integers x less than 16 such that x2 is
Z} an even number.
All the requirements x Î Z≥, x < 16, x2 = 2k for some k Î Z
must hold for an integer x to qualify to belong to this set.
Case 1: If x = 0 then x2 = 0 and 0 Î Z≥, 0 < 16, 02 = 2(0) for
some k = 0 ∈ Z.
Case 2: If x = 2 then x2 = 4 and 2 Î Z≥, 2 < 16, 22 = 2(2) for
some k = 2 ∈ Z.
And so we can go on to see that for all non-negative
integers x = 0, 2, 4, 6, 8, 10, 12, 14 it will be the case that
x2 = 2k, k ∈ Z, and also note that x < 16.
If x = 1, 3, 5, 7, 9, 11, 13, 15 then x does not qualify to
belong to the required set since x is an odd number and
thus x2 is also an odd number.
Refer to study guide, pp 3, 7, 11, 35 – 39.
b. {x| x ∈ Z≥, x < 16, x2 = 2k for some k ∈ Z+}
c. {0, 2, 4, 16, 36, 64, 100, 144, 196}
d. {0, 2, 4}
Refer to study guide, pp 3, 7, 11, 35 – 39.
The correct answer is: {x| x ∈ Z≥, x < 16, x2 = 2k for some k ∈ Z}
https://mymodules.dtls.unisa.ac.za/mod/quiz/review.php?attempt=10149394&cmid=618676 2023/10/31, 9 08 AM
Page 2 of 10
:
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying these notes from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller drowsy-polls0j. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy these notes for $2.94. You're not tied to anything after your purchase.
Can Stuvia be trusted?
4.6 stars on Google & Trustpilot (+1000 reviews)
80189 documents were sold in the last 30 days
Founded in 2010, the go-to place to buy study notes for 14 years now