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Pearson Edexcel Level 3 GCE Chemistry Advanced Subsidiary PAPER 1: Core Inorganic and Physical Chemistry june 2023 $15.49   Add to cart
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Pearson Edexcel Level 3 GCE Chemistry Advanced Subsidiary PAPER 1: Core Inorganic and Physical Chemistry june 2023
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Pearson Edexcel Level 3 GCE Chemistry Advanced Subsidiary PAPER 1: Core Inorganic and Physical Chemistry june 2023

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  • January 6, 2024
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  • 2023/2024
  • Exam (elaborations)
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  • june 2023
  • pearson edexcel level 3 gce chemistry advanced
  • paper 1 core inorganic and physical chemistry

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  • PEARSON (PEARSON)
  • Chemistry
  • Chemistry
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Please check the examination details below before entering your candidate
information
Candidate surname Other names

Centre Candidate
Number Number


Pearson Edexcel Level 3
GCE
Tuesday 16 May 2023
Paper
Morning (Time: 1 hour 30
minutes)
referenc
e
8CH0/01
 
Chemistry
Advanced Subsidiary
PAPER 1: Core Inorganic and Physical
Chemistry
You must have: Total
Scientific calculator, Data Booklet, ruler Marks



Instructions
•• Use black ink or ball‑point pen.
If pencil is used for diagrams/sketches/graphs it must be dark (HB or B).
• Fill in the boxes at the top of this page with your name,
centre number and candidate number.
•• Answer all
Answer the questions in the spaces
provided – there may be more space than
you need.
questions.
Information
• The total mark for this paper is 80.
• The marks for each question are shown in brackets
– use this as a guide as to how much time to spend on each question.
• For the question marked with an asterisk (*), marks will be awarded for
your ability to structure your answer logically, showing the points that you
make are related or follow on from each other where appropriate.
• A Periodic Table is printed on the back cover of this paper.
Advice
•• Read each question carefully before you start to answer it.
Show all your working in calculations and include units where
• appropriate. Check your answers if you have time at the end.
Turn over




1

, Answer ALL questions.

Some questions must be answered with a cross in a box . If you
change your mind about an answer, put a line through the box and
then mark your new answer with a cross .

1 Atoms of silicon contain protons, neutrons and electrons.

(a) Which are the correct data for a proton and a neutron?
(1)

Proton Neutron

Relative charge Relative mass Relative charge Relative mass
A +1 1 –1 0.0005
B
+1 1 0 1
C
–1 0.0005 0 1
D
0 1 +1 1


(b) (i) State the shape of the 2s orbital of a silicon
atom. (1)

. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. ..
. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. ......................



(ii) State the difference between the two subatomic particles in the 2s
orbital. (1)

. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. ..
. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. ......................




2


, (c) Silicon has three stable isotopes.
A sample of silicon was found to have a relative atomic mass, Ar , of 28.11
due to the presence of only the three stable isotopes.
The abundance for two of the isotopes is given in the table.


Isotope Abundance / %
28
Si 92.2
30
Si 3.1


Determine the relative isotopic mass of the third stable
isotope. You must show your working.
(2)




(d) Give the symbol, including the mass number and atomic number, for an
atom of element X that has four fewer protons and three fewer neutrons
than 28Si.
1 an atom of
4 (1)



. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. ..
. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. ......................



(Total for Question 1 = 6 marks)




3
 Turn
over

, 2 This question is about the double salt K2Mg(SO4)2.6H2O.
A double salt is a salt containing more than one cation or more than one
anion.
(a) (i) Give the reason why the term relative formula mass is used, rather
than relative molecular mass, when discussing K2Mg(SO4)2.6H2O. (1)

. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. ..
. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. ......................



. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. ..
. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. ......................



. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. ..
. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. .. . .. .. .. .. ... .. .. .. .. .. .. .. .. ......................




(ii) Give the reason why relative formula mass has no mathematical
units. (1)

. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. ..
. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. ......................



. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. ..
. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. .. . .. .. .. .. ... .. .. .. .. .. .. .. .. ......................



. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. ..
. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. . . .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. ......................



. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. ..
. .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. . .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. ... .. .. .. .. .. .. .. .. .. .. ... .. .. .. .. ... .. .. .. .. .. .. .. .. ......................




(iii) What is the relative formula mass of
K2Mg(SO4)2.6H2O? Use the Periodic Table as a
source of data. (1)

A 206.0
B 322.7
C 402.7
D 595.3


(iv) Calculate the amount of substance, in mol, in 25.0 g of (1)
K2Mg(SO4)2.6H2O.




4


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