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ORGANIC CHEMISTRY 8Th Ed International Edition by John E. McMurry - Test Bank $26.82   Add to cart

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ORGANIC CHEMISTRY 8Th Ed International Edition by John E. McMurry - Test Bank

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ORGANIC CHEMISTRY 8Th Ed International Edition by John E. McMurry - Test Bank

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  • January 2, 2024
  • 593
  • 2022/2023
  • Exam (elaborations)
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,Chapter 1—Structure and Bonding


SHORT ANSWER

1. Give the ground-state electron configuration for carbon (atomic number 6).

ANS:
1s22s22px12py1 or 1s22s22p2


2. Give the ground-state electron configuration for fluorine (atomic number 9).

ANS:
1s22s22px2 2py2 2pz1 or 1s22s22p5


3. Give the ground-state electron configuration for magnesium (atomic number 12).

ANS:
1s22s22p63s2


4. How many electrons does silicon have in its valence shell?

ANS:
four


Exhibit 1-1
Write valid Lewis (electron-dot) structures for each formula below. Show all electrons as dots and
show all non-bonding electrons.

5. C2Cl4 tetrachloroethylene

ANS:




6. CO2 carbon dioxide

ANS:



7. CH4O methanol




1

,Structure and Bonding


ANS:




Exhibit 1-2
Consider the structure of urea, shown below, to answer the following question(s).




8. Refer to Exhibit 1-2. Fill in any non-bonding valence electrons that are missing from the
line-bond structure.

ANS:




9. Refer to Exhibit 1-2. The carbon atom in urea is:

a. sp3 hybridized
b. sp2 hybridized
c. sp hybridized
d. not hybridized

ANS:
b


10. Refer to Exhibit 1-2. The predicted NH2−C=O bond angle in urea is:

a. 109.5°
b. 120°
c. 180°
d. not predictable

ANS:
b




2

, Chapter 1


Exhibit 1-3
Determine the hybridization for the indicated atoms in each structure below.




11. Refer to Exhibit 1-3. The hybridization of this oxygen atom (A) is ______.

ANS:
sp2


12. Refer to Exhibit 1-3. The hybridization of this oxygen atom (B) is ______.

ANS:
sp3


13. Refer to Exhibit 1-3. The hybridization of this carbon atom (C) is ______.

ANS:
sp3


14. Refer to Exhibit 1-3. The hybridization of this carbon atom (D) is ______.

ANS:
sp


15. The molecular formula C2H4O can be converted into three-line bond (Kekulé) structures that
are consistent with valence rules.

a. b. c. d.




a. Which one of the Kekulé structures is not consistent with valence rules?
b. Explain why the structure you chose in part a is not consistent with valence rules.

ANS:
a. d
b. The carbon bonded to the oxygen atom in structure d is pentavalent; it has 10 valence
electrons. Carbon can only have eight valence electrons. In addition, the other carbon
has only six valence electrons when it would prefer to have eight.




3

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