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Summary Derivation of the Michaelis-Menten Equation

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  • October 8, 2023
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Derivation of the Michaelis-Menten Equation

The Michaelis-Menten equation is an important equation in biochemistry and as

such it is imperative that you understand the derivation of this equation. By

understanding the derivation, you will have insight into the assumptions that went into

this model, and therefore you will have a better appreciation for the proper use of this

equation as well as the limitations of this model. In the following sections you will see

two different derivations of the Michaelis-Menten equation. When one is learning a

subject for the first time, it often helps to have the same or similar information presented

from alternative perspectives. One way might be clearer to you whereas the other way

might be clearer to someone else. That is ok! You should familiarize yourself with both

approaches, and then settle on the one that you prefer. The first derivation was adapted

from “An Introduction to Enzyme Kinetics” by Addison Ault (J. Chem. Ed. 1974, 51,

381 – 386).

First Derivation. We start with the kinetic mechanism shown in equation (eq) 1:

k1 k3
E + S ES E + P
k2 (1)

In eq 1, E is enzyme, S is substrate, ES is the enzyme-substrate complex, and P is

product. This equation includes the assumption that during the early stages of the reaction

so little product is formed that the reverse reaction (product combining with enzyme and

re-forming substrate) can be ignored (hence the unidirectional arrow under k3). Another

assumption is that the concentration of substrate is much greater than that of total enzyme

([S] >> [Et]), so it can essentially be treated as a constant.




1

, From General Chemistry we can equate the rate of this process (k3[ES]) to the

change in product concentration as a function of time (d[P]/dt), or, equivalently, we can

designate the rate with an italicized v (v) as follows in eq 2:

d [P]
 v  k 3 [ES] (2)
dt

Because the concentration of the enzyme•substrate complex ([ES]) cannot be measured

experimentally, we need an alternative expression for this term. Because the enzyme that

we add to the reaction will either be unbound (E) or bound (ES) we can express the

fraction of bound enzyme as follows:

[ES] [ES]
 (3)
[E t ] [ES]  [E ]

In eq 3 Et is the concentration of total enzyme, and the other variables are as defined

above. If we multiply both sides of eq 3 by Et we arrive at eq 4:

[E t ][ES]
[ES]  (4)
[ES]  [E]

If we multiply the numerator and denominator of the right-hand side of eq 4 by 1/[ES],

we are, in effect, multiplying by one and we do not change the value of this expression.

When we do this we obtain eq 5:

[E t ]
[ES]  (5)
[E]
1
[ES]

We have almost achieved our goal of isolating [ES]. Next, we need to come up with an

alternative expression for the ratio [E]/[ES]. We do this by recalling that a major

assumption in enzyme kinetics is the steady-state assumption. Basically, it says the rate

of change of [ES] as a function of time is zero: d[ES]/dt = 0. Another way to express the



2

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