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Bishop: Clinical Chemistry| 420 Questions | With Complete Solutions $17.99   Add to cart

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Bishop: Clinical Chemistry| 420 Questions | With Complete Solutions

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  • Course
  • Clinical Chemistry
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  • Clinical Chemistry

What is the molarity for a solution containing 100 g of NaCl made up to 500 mL with distilled water? Assume a gram molecular weight (from periodic table) of approximately 58 grams. a. 3.45 M b. 1.72 M c. 290 M d. 5.27 M correct answer: a. 3.45 M What is the normality for a solution conta...

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  • September 6, 2023
  • 107
  • 2023/2024
  • Exam (elaborations)
  • Questions & answers
  • Clinical Chemistry
  • Clinical Chemistry
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Bishop: Clinical Chemistry| 420 Questions |
With Complete Solutions
What is the molarity for a solution containing 100 g of NaCl made up to 500 mL with distilled water? Assume a gram molecular weight (from periodic table) of approximately 58 grams.
a. 3.45 M b. 1.72 M c. 290 M d. 5.27 M correct answer: a. 3.45 M
What is the normality for a solution containing 100 g of NaCl made up to 500 mL with distilled water? Assume a gram molecular weight (from periodic table) of approximately 58 grams.
a. 3.45 b. 0.86 c. 1.72 d. 6.9 correct answer: a. 3.45
What is the percent (w/v) for a solution containing 100 g of NaCl made up to 500 mL with distilled water?
a. 20% b. 5% c. 29% d. 58% correct answer: a. 20% What is the dilution factor for a solution containing 100 g of NaCl made up to 500 mL with distilled water?
a. 1:5 or 1/5 b. 5
c. 50 or 1/50 d. 10 correct answer: a. 1:5 or 1/5
What is the value in mg/dL for a solution containing 10 mg of CaCl2 made with 100 mL of distilled water?
a. 10
b. 100
c. 50
d. Cannot determine without additional information correct answer: a. 10
What is the molarity of a solution containing 10
mg of CaCl2 made with 100 mL of distilled water? Assume a gram molecular weight from the periodic table of approximately
111 grams.
a. 9 × 10-4 b. 1.1 × 10-3 c. 11.1
d. 90 correct answer: a. 9 x 10-4
You must make 1L of 0.2M acetic acid(CH3COOH). All you have available is concentrated glacial acetic acid (assay value, 98%; specific gravity, 1.05 g/mL). It will take ______ milliliters
of acetic acid to make this solution. Assume a gram molecular weight of 60.05 grams.
a. 11.7 b. 1.029 c. 3.42 d. 12.01 correct answer: a. 11.7
What is the hydrogen ion concentration of an acetate buffer having a pH of 4.24?
a. 5.75 × 10-5 b. 1.19 × 10-1 c. 0.62
d. 0.76 × 10-4 correct answer: a. 5.75 x 10-5
Using the Henderson-Hasselbalch equation, give the ratio of salt
to weak acid for a Veronal buffer withapHof8.6andapKa of 7.43.
a. 14.7/1 b. 1/8.6 c. 1.17/1 d. 1/4.3 correct answer: a. 14.7/1
The pKa for acetic acid is 4.76. If the concentra- tion of salt is 5 mmol/L and that of acetic acid is 10 mmol/L, what is the expected pH?
a. 4.46 b. 5.06 c. 104 d. 56 correct answer: a. 4.46
The hydrogen ion concentration of a solution is 0.0000937. What is the pH?
a. 4.03
b. 9.37 × 10-5 c. 9.07
d. 8.03 correct answer: a. 4.03. Perform the following conversions: 4×104 mg=___g
1.3×102 mL=____dL
0.02 mL = ____ μL
5×10-3 mL=___μL 5×10-2 L=___mL 4 cm = _____ mm correct answer: 4×104 mg= 40 g
1.3×102 mL= 1.3 dL
0.02 mL = 20 μL
5×10-3 mL= 5 μL 5×10-2 L= 50 mL 4 cm = 40 mm
What volume of 14 N H2SO4 is needed to make
250 mL of 3.2 M H2SO4 solution? Assume a gram
molecular weight of 98.08 grams. a. 114 mL
b. 1.82 mL
c. 1.75 mL
d. 7 mL correct answer: a. 114 mL
A 1:200 dilution of the urine specimen gives a creatinine result of 0.8 mg/dL. The serum value is 1.2 mg/dL. What is the final value of creatinine in mg/dL in the undiluted urine sample?
a. 160 b. 0.8 c. 960 d. 860 correct answer: a. 160

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