100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
Solution Manual for Shigley's Mechanical Engineering Design 10th Edition by Richard Budynas, Keith Nisbett $17.49   Add to cart

Exam (elaborations)

Solution Manual for Shigley's Mechanical Engineering Design 10th Edition by Richard Budynas, Keith Nisbett

 136 views  2 purchases
  • Course
  • SM+TB
  • Institution
  • SM+TB

Solution Manual for Shigley's Mechanical Engineering Design 10th Edition by Richard Budynas, Keith Nisbett

Preview 4 out of 739  pages

  • August 11, 2023
  • 739
  • 2023/2024
  • Exam (elaborations)
  • Questions & answers
book image

Book Title:

Author(s):

  • Edition:
  • ISBN:
  • Edition:
  • SM+TB
  • SM+TB
avatar-seller
solutions
Solution Manual for All Chapters Shigley’s MED, 10th edition Chapter 15 Solutions , Page 1/20 Chapter 1 Problems 1-1 through 1-6 are for student research. No standard solutions are provided. 1-7 From Fig. 1 -2, cost of grinding to  0.0005 in is 270%. Cost of turning to  0.003 in is 60%. Relative cost of grinding vs. turning = 270/60 = 4.5 times Ans. ______________________________________________________________________________ 1-8 CA = CB, 10 + 0.8 P = 60 + 0.8 P  0.005 P 2 P 2 = 50/0.005  P = 100 parts Ans. ______________________________________________________________________________ 1-9 Max. load = 1.10 P Min. area = (0.95)2A Min. strength = 0.85 S To offset the absolute uncertainties, the design factor, from Eq. (1 -1) should be 21.101.43 .
0.85 0.95dn Ans ______________________________________________________________________________ 1-10 (a) X1 + X2: 1 2 1 1 2 2
1 2 1 2
12error .x x X e X e
e x x X X
e e Ans    
    
 (b) X1  X2: 
1 2 1 1 2 2
1 2 1 2 1 2 .x x X e X e
e x x X X e e Ans    
      (c) X1 X2: 1 2 1 1 2 2
1 2 1 2 1 2 2 1 1 2
12
1 2 2 1 1 2
12 .x x X e X e
e x x X X X e X e e e
eeX e X e X X AnsXX  
    
    
 Solution Manual for All Chapters Shigley’s MED, 10th edition Chapter 15 Solutions , Page 2/20 (d) X1/X2: 1 1 1 1 1 1
2 2 2 2 2 2
1
2 2 1 1 1 2 1 2
2 2 2 2 1 2 1 2
1 1 1 1 2
2 2 2 1 21
1
11 1 then 1 1 11
Thus, .x X e X e X
x X e X e X
e e e X e e e e
X X e X X X X X
x X X e ee Ansx X X X X 
                            
    
 ______________________________________________________________________________ 1-11 (a) x1 = 7 = 2.645 751 311 1 X1 = 2.64 (3 correct digits) x2 = 8 = 2.828 427 124 7 X2 = 2.82 (3 correct digits) x1 + x2 = 5.474 178 435 8 e1 = x1  X1 = 0.005 751 311 1 e2 = x2  X2 = 0.008 427 124 7 e = e1 + e2 = 0.0 14 178 435 8 Sum = x1 + x2 = X1 + X2 + e = 2.64 + 2.82 + 0.014 178 435 8 = 5.474 178 435 8 Checks (b) X1 = 2.65, X2 = 2.83 (3 digit significant numbers) e1 = x1  X1 =  0.004 248 688 9 e2 = x2  X2 =  0.001 572 875 3 e = e1 + e2 =  0.005 821 564 2 Sum = x1 + x2 = X1 + X2 + e = 2.65 +2.83  0.001 572 875 3 = 5.474 178 435 8 Checks ______________________________________________________________________________ 1-12 3
325 10 32 10001.006 in .2.5dSd Ansnd     Table A-17: d = 1
41 in Ans. Factor of safety: 

3
325 10
4.79 .32 1000
1.25Sn Ans
   ______________________________________________________________________________ Solution Manual for All Chapters Shigley’s MED, 10th edition Chapter 15 Solutions , Page 3/20 1-13 (a) Eq. (1-6) 11 8480122.9 kcycles69k
ii
ix f xN   Eq. (1-7) 221/ 22
1 1104 600 69(122.9)30.3 kcycles .1 69 1k
ii
i
xf x N x
s AnsN      (b) Eq. (1 -5) 115
115115 122.90.2607ˆ 30.3x
xxx x xzs
       Interpolating from Table (A -10) 0.2600 0.3974 0.2607 x  x = 0.3971 0.2700 0.3936 N(0.2607) = 69 (0.3971) = 27.4  27 Ans. From the data, the number of instances less than 115 kcycles is x f f x f x2 60 2 120 7200 70 1 70 4900 80 3 240 19200 90 5 450 40500 100 8 800 80000 110 12 1320 145200 120 6 720 86400 130 10 1300 169000 140 8 1120 156800 150 5 750 112500 160 2 320 51200 170 3 510 86700 180 2 360 64800 190 1 190 36100 200 0 0 0 210 1 210 44100  69 8480 1 104 600 Solution Manual for All Chapters Shigley’s MED, 10th edition Chapter 15 Solutions , Page 4/20 2 + 1 + 3 + 5 + 8 + 12 = 31 (the data is not perfectly normal) ____________________________________________________________________________ 1-14 x f f x f x2 174 6 1044 181656 182 9 1638 298116 190 44 8360 1588400 198 67 13266 2626668 206 53 10918 2249108 214 12 2568 549552 222 6 1332 295704  197 39126 7789204 Eq. (1-6) 11 39 126198.61 kpsi197k
ii
ix f xN   Eq. (1 -7) 22122
1 7 789 204 197(198.61)9.68 kpsi .1 197 1k
ii
i
xf x N x
s AnsN     ______________________________________________________________________________ 1-15 122.9 kcycles and 30.3 kcyclesL Ls Eq. (1 -5) 10 10
10122.9
ˆ 30.3x
Lx x L xzs
     Thus, x10 = 122.9 + 30.3 z10 = L10 From Table A-10, for 10 percent failure, z10 = 1.282 . Thus, L10 = 122.9 + 30.3( 1.282) = 84.1 kcycles Ans. ___________________________________________________________________________

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller solutions. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $17.49. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

79650 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$17.49  2x  sold
  • (0)
  Add to cart