100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
Class notes Physics formulas $10.49   Add to cart

Interview

Class notes Physics formulas

 2 views  0 purchase
  • Course
  • Institution

Unlock the Power of Physics: Comprehensive Topic-wise Notes, Formulas, and Summaries! Looking for a comprehensive and organized resource to master physics concepts? Our Physics Notes Formula and Summary Book is your ultimate guide to unravel the mysteries of the universe. Designed for students, ...

[Show more]

Preview 2 out of 11  pages

  • August 2, 2023
  • 11
  • 2023/2024
  • Interview
  • Unknown
  • Unknown
  • Secondary school
  • 3
avatar-seller
Formulae S he e t f o r P h ys i c s w w w .c o n c e p t s - o f -p h y s i c s . c om | pg. 1

Physics formulas from Mechanics, Waves, Optics, Heat and Motion in a straight line with constant a:
Thermodynamics, Electricity and Magnetism and Modern
Physics. Also includes the value of Physical Constants. Helps v = u + at, s = ut + 21 at2 , v 2 − u2 = 2as
in quick revision for CBSE, NEET, JEE Mains, and Advanced.
Relative Velocity: ~vA/B = ~vA − ~vB
0.1: Physical Constants

Speed of light c 3 × 108 m/s
u
Planck constant h 6.63 × 10−34 J s y




u sin θ
hc 1242 eV-nm H
x
Projectile Motion:
Gravitation constant G 6.67×10−11 m3 kg−1 s−2 θ
Boltzmann constant k 1.38 × 10−23 J/K O u cos θ
Molar gas constant R 8.314 J/(mol K) R

Avogadro’s number NA 6.023 × 1023 mol−1
Charge of electron e 1.602 × 10−19 C x = ut cos θ, y = ut sin θ − 21 gt2
Permeability of vac- µ0 4π × 10−7 N/A2 g
y = x tan θ − 2 x2
uum 2u cos2 θ
Permitivity of vacuum 0 8.85 × 10−12 F/m 2u sin θ u2 sin 2θ u2 sin2 θ
T = , R= , H=
Coulomb constant 1
4π0 9 × 109 N m2 /C2 g g 2g
Faraday constant F 96485 C/mol
Mass of electron me 9.1 × 10−31 kg 1.3: Newton’s Laws and Friction
Mass of proton mp 1.6726 × 10−27 kg
Mass of neutron mn 1.6749 × 10−27 kg Linear momentum: p~ = m~v
Atomic mass unit u 1.66 × 10−27 kg
Atomic mass unit u 931.49 MeV/c2 Newton’s first law: inertial frame.
Stefan-Boltzmann σ 5.67×10−8 W/(m2 K4 )
Newton’s second law: F~ = d~
p
dt , F~ = m~a
constant
Rydberg constant R∞ 1.097 × 107 m−1 Newton’s third law: F~AB = −F~BA
Bohr magneton µB 9.27 × 10−24 J/T
Bohr radius a0 0.529 × 10−10 m Frictional force: fstatic, max = µs N, fkinetic = µk N
Standard atmosphere atm 1.01325 × 105 Pa
v2 v2
Wien displacement b 2.9 × 10−3 m K Banking angle: rg = tan θ, rg = µ+tan θ
1−µ tan θ
constant
mv 2 v2
Centripetal force: Fc = r , ac = r
2

1 MECHANICS Pseudo force: F~pseudo = −m~a0 , Fcentrifugal = − mv
r

Minimum speed to complete vertical circle:
1.1: Vectors
p p
vmin, bottom = 5gl, vmin, top = gl
Notation: ~a = ax ı̂ + ay ̂ + az k̂
q
Magnitude: a = |~a| = a2x + a2y + a2z θ
l
q
l cos θ
Conical pendulum: T = 2π θ T
Dot product: ~a · ~b = ax bx + ay by + az bz = ab cos θ g


ı̂ mg
a × ~b
~ ~b
Cross product:
θ k̂ ̂
~
a
1.4: Work, Power and Energy
~a ×~b = (ay bz − az by )ı̂ + (az bx − ax bz )̂ + (ax by − ay bx )k̂ Work: W = F~ · S
~ = F S cos θ, W =
R
F~ · dS
~

|~a × ~b| = ab sin θ Kinetic energy: K = 12 mv 2 = p2
2m

Potential energy: F = −∂U/∂x for conservative forces.
1.2: Kinematics
Ugravitational = mgh, Uspring = 21 kx2
Average and Instantaneous Vel. and Accel.:

~vav = ∆~r/∆t, ~vinst = d~r/dt Work done by conservative forces is path indepen-
dent and depends only on initial and final points:
~aav = ∆~v /∆t ~ainst = d~v /dt H
F~conservative · d~r = 0.

Work-energy theorem: W = ∆K



Get Formulas www.concepts-of-physics.com Get Our Book
c 2020 by Jitender Singh Ver. 2020 1

, Formulae S he e t f o r P h ys i c s w w w .c o n c e p t s - o f -p h y s i c s . c om | pg. 2

Mechanical energy: E = U + K. Conserved if forces are Rotation about an axis with constant α:
conservative in nature.
ω = ω0 + αt, θ = ωt + 21 αt2 , ω 2 − ω0 2 = 2αθ
Power Pav = ∆W
∆t , Pinst = F~ · ~v

mi ri 2 , r2 dm
P R
Moment of Inertia: I = i I=
1.5: Centre of Mass and Collision
P R
R xdm
2
Pxi mi ,
1
2 mr m(a +b )
2 2
Centre of mass: xcm = xcm = mr 2 1 2 2 2 2 2 1 2 mr 2
mi dm 2 mr 3 mr 5 mr 12 ml 12


b
a
CM of few useful configurations: ring disk shell sphere rod hollow solid rectangle

m1 r m2
1. m1 , m2 separated by r: C
m2 r m1 r Ik Ic
m1 +m2 m1 +m2 2
Theorem of Parallel Axes: Ik = Icm + md d
cm
h
2. Triangle (CM ≡ Centroid) yc = 3 h
C
h
3
z y
Theorem of Perp. Axes: Iz = Ix + Iy
2r
x
3. Semicircular ring: yc = π
C
2r
r π
p
Radius of Gyration: k = I/m
4r
4. Semicircular disc: yc = 3π C 4r
r ~ = ~r × p~, ~ = I~
3π Angular Momentum: L L ω
r y
5. Hemispherical shell: yc = 2 C r ~ P θ ~
r 2
Torque: ~τ = ~r × F~ , ~τ = dL
dt , τ = Iα F
~
r x
O
3r
6. Solid Hemisphere: yc = 8 C 3r
r 8 ~ ~τext = 0 =⇒ L ~ = const.
Conservation of L:
7. Cone: the height of CM from the base is h/4 for Equilibrium condition:
P~
F = ~0,
P
~τ = ~0
the solid cone and h/3 for the hollow cone.
Kinetic Energy: Krot = 12 Iω 2

Motion of the CM: M =
P
mi Dynamics:
P
mi~vi F~ext ~τcm = Icm α
~, F~ext = m~acm , p~cm = m~vcm
~vcm = , p~cm = M~vcm , ~acm = 1 2 1 2 ~
M M ~ + ~rcm × m~vcm
K = 2 mvcm + 2 Icm ω , L = Icm ω

Impulse: J~ = F~ dt = ∆~
R
p
1.7: Gravitation
Before collision After collision
Collision: m1 m2 m1 m2 m1 F F m2
Gravitational force: F = G mr1 m
2
2

v1 v2 v10 v20 r
Momentum conservation: m1 v1 +m2 v2 = m1 v10 +m2 v20
2
Elastic Collision: 12 m1 v1 2+ 12 m2 v2 2 = 12 m1 v10 + 12 m2 v20
2 Potential energy: U = − GMr m
Coefficient of restitution: GM
Gravitational acceleration: g = R2
−(v10 − v20 )

1, completely elastic
e= = h

v1 − v2 0, completely in-elastic Variation of g with depth: ginside ≈ g 1 − R

2h

Variation of g with height: goutside ≈ g 1 −
If v2 = 0 and m1
m2 then v10 = −v1 . R

If v2 = 0 and m1
m2 then v20 = 2v1 . Effect of non-spherical earth shape on g:
Elastic collision with m1 = m2 : v10 = v2 and v20 = v1 . gat pole > gat equator (∵ Re − Rp ≈ 21 km)

Effect of earth rotation on apparent weight:
1.6: Rigid Body Dynamics
∆θ dθ
Angular velocity: ωav = ∆t , ω= dt , ~ × ~r
~v = ω
∆ω dω
Angular Accel.: αav = ∆t , α= dt , ~ × ~r
~a = α



Get Formulas www.concepts-of-physics.com Get Our Book
c 2020 by Jitender Singh Ver. 2020 1

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller ashutoshsharma3. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $10.49. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

72042 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$10.49
  • (0)
  Add to cart