Test Bank to Accompany Life The Science of Biology, 11th Edition Sadava, Hillis, Heller, Hacker
Table of Contents Chapter 5: Cells: The Working Units of Life ................................................................................. 1 Chapter 6: Cell Membranes .................................
Test Bank to Accompany Life The Science of Biology, 11th Edition Sadava, Hillis,
Heller, Hacker
Table of Contents
Chapter 5: Cells: The Working Units of Life ................................................................................. 1
Chapter 6: Cell Membranes ....................................................................................................... 86
Chapter 7: Cell Communication and Multicellularity ................................................................. 185
Chapter 9: Pathways That Harvest Chemical Energy .............................................................. 291
Chapter 10: Photosynthesis: Energy from Sunlight .................................................................. 392
Chapter 5: Cells: The Working Units of Life
TEST BANK QUESTIONS
Multiple Choice
1. Which statement is one of the tenets of cell theory?
a. All cells take in energy and matter from the environment.
b. Cells are separated from their environment by a cell membrane.
c. All cells come from preexisting cells.
d. All cells contain mitochondria.
e. Cells sustain the living state through chemical
transformations.Answer: c
Learning Outcome: 5.1.1.a List the three tenets of the original cell theory.
Bloom’s Level: 1. Remembering
2. A student claims that the study of cell biology can be considered the same as
studyinglife. Which statement makes the best response to this student’s claim?
a. No, the claim is not correct because many organisms are composed of many cells,
andso the study of cells alone is not sufficient to study life.
b. No, the claim is not correct because cells are microscopic and do not represent
mostliving things as we observe them in nature.
c. Yes, the claim is correct because cells are the smallest biological unit that expresses
allof the same principles of life found in all organisms.
d. Yes, the claim is correct because individual cells are easier to study than
multicellularorganisms that have complex intercellular interactions.
e. Yes, the claim is correct because all cells share similar characteristics that allow
themto be studied as a group.
Answer: c
Learning Outcome: 5.1.1.b Justify the statement that studying cell biology can
beconsidered the same as studying life.
Bloom’s Level: 5. Evaluating
3. A student claims that the image below demonstrates that life is continuous.
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,Which statement best evaluates the student’s claim?
a. The claim is supported because the image shows how the cell acquires matter from
theenvironment.
b. The claim is supported because the image provides information about how the
cellobtains energy from its surroundings.
c. The claim is supported because the image illustrates how a cell can respond to
itsenvironment.
d. The claim is not supported because the image does not show how the cell reproduces
toform new daughter cells.
e. The claim is not supported because the image does not show how the cell
transformsmatter to make it useful for its continued survival.
Answer: d
Learning Outcome: 5.1.1.c Use an example to illustrate the claim that life is
continuous.Bloom’s Level: 3. Applying
4. Many pieces of evidence support the claim that all modern cells share the same
ancestor in their evolutionary histories. If a living organism is discovered on another
planet or moon, what data would biologists collect to determine whether this
organismalso shares the common ancestor that all cells on Earth share?
a. The organism’s ability to survive in Earth’s atmosphere
b. The ability of the organism to reproduce itself
c. The chemical composition of the organism’s hereditary molecules
d. The presence of water in the organism’s internal environment
e. The organism’s ability to extract energy from its external environment
Answer: c
Learning Outcome: 5.1.2.a Describe the evolutionary history of modern cells.
Bloom’s Level: 3. Applying
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,5. Five statements comparing prokaryotes and eukaryotes are given. Which
statementprovides evidence that supports the claim that all cells share a common
ancestor?
a. Prokaryotes and eukaryotes use the same genetic code.
b. There are many examples of both prokaryotes and eukaryotes that use flagella
forlocomotion.
c. The DNA present in mitochondria of eukaryotes shares more overlap with prokaryotic
DNA than with eukaryotic nuclear DNA.
d. Prokaryotic cells are generally smaller than eukaryotic cells.
e. DNA in eukaryotic cells is enclosed in a membrane-bound nucleus, and DNA in
prokaryotic cells resides in the nucleoid, which is not separated from the
cytoplasm.Answer: a
Learning Outcome: 5.1.2.a Describe the evolutionary history of modern cells.
Bloom’s Level: 5. Evaluating
6. How does the surface area-to-volume ratio of a sphere 1 mm in diameter compare
withthe surface area-to-volume ratio of a sphere 3 mm in diameter?
a. The comparison depends on the components of the two spheres.
b. The 3 mm sphere has a higher ratio than the 1 mm sphere.
c. The 1 mm sphere has a ratio that is one-third that of the 3 mm sphere.
d. The 1 mm sphere has a ratio three times larger than that of the 3 mm sphere.
e. The ratios are the
same.Answer: d
Learning Outcome: 5.1.3.a Compare the surface area-to-volume ratios of cells of
different dimensions and predict how well they exchange energy and matter with the
environment.
Bloom’s Level: 3. Applying
7. Though science fiction has produced stories like The Blob, we do not see many
large,single-celled organisms. Which is a reason for the limitation to cell size?
a. The difficulty of maintaining a continuous membrane around a large cell
b. The difficulty of reproducing a large cell
c. The difficulty of moving molecules rapidly within a large cell
d. The difficulty of DNA replication in a large cell
e. The difficulty of synthesizing proteins in a large cell
Answer: c
Learning Outcome: 5.1.3.b Explain the limitations on cell size.
Bloom’s Level: 2. Understanding
8. The surface area-to-volume ratio of a cell
a. increases with increasing volume of the cell.
b. decreases with decreasing surface area of the cell.
c. accounts for the size limit of cells.
d. is of little significance in maintaining cell homeostasis.
e. affects how molecules are distributed across the
cell.Answer: c
Learning Outcome: 5.1.3.b Explain the limitations on cell size.
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, Bloom’s Level: 2. Understanding
9. Which cell carries out the most chemical activity within a minute (all else being
equal)?
a. A spherical cell 1 m in diameter
b. A spherical cell 2 m in diameter
c. A spherical cell 3 m in diameter
d. A spherical cell 4 m in diameter
e. A nonspherical cell of any diameter
Answer: d
Learning Outcome: 5.1.3.b Explain the limitations on cell size.
Bloom’s Level: 3. Applying
10. Which cell exchanges the most substances and waste products with its
environmentrelative to its internal chemical activity?
a. A spherical cell 1 m in diameter
b. A spherical cell 2 m in diameter
c. A spherical cell 3 m in diameter
d. A spherical cell 4 m in diameter
e. A nonspherical cell of any diameter
Answer: a
Learning Outcome: 5.1.3.b Explain the limitations on cell size.
Bloom’s Level: 3. Applying
11. Most plant and animal cells are
a. smaller than a chloroplast.
b. smaller than most bacteria.
c. larger than most fungal cells.
d. large enough to be seen with the unaided eye.
e. large enough to be seen with a light
microscope.Answer: e
Learning Outcome: 5.1.4.a Describe ways that microscopy is used to study cells.
Bloom’s Level: 2. Understanding
12. Which technique would be best suited to a study of normal cell migration during
embryonic development?
a. Direct visual observation
b. Light microscopy
c. Electron microscopy
d. Cell fractionation
e. Experimentation on
mutantsAnswer: b
Learning Outcome: 5.1.4.a Describe ways that microscopy is used to study cells.
Bloom’s Level: 3. Applying
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