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COS assignment 2 solution

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COS assignment 2 solution with source code and link to the zipped files. Create a C++ program that will display a binary search tree: inorder traversal, preorder traversal, postorder traversal and height of the tree. The nodes of the binary search tree will be read into the code using a text file....

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  • July 13, 2023
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  • 2022/2023
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COS2611 2023 ASSIGNMENT 2
SOLUTION(100% working)
Link to the zipped file is provided at the end of this
document

Crystal Indigo!
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Copy and run the code and submit what you are suppose to submit

,Outputs:

,Question 1
// COS2611 Skeleton for Assessment 3
#include <iostream>
#include <fstream>
#include <string>
#include<vector>

//Add your student name and student number
//
//
//



using namespace std;

class TreeNode
{
//keep this class as is
public:

int value; //key or data
TreeNode* left;
TreeNode* right;

//constructors

TreeNode() {
value = 0;
left = NULL;
right = NULL;
} //default constructor

TreeNode(int v) {
value = v;
left = NULL;
right = NULL;
} //parametrized constructor

}; //TreeNode



class BST
{
public:
TreeNode* root;

//member functions

BST() {
root = NULL;

, }

bool isTreeEmpty()
{
if (root == NULL)
return true; //the tree is empty
else
return false; //the tree is not empty
}

void insertNode(TreeNode* new_node) {
if (root == NULL) {
root = new_node;
} //insert the root node
else {
TreeNode* temp = root;
while (temp != NULL) {
if (new_node->value == temp->value) {
cout << "Value Already exist," <<
"Insert another value!" << endl;
return;
}
else if ((new_node->value < temp->value) && (temp->left == NULL)) {
temp->left = new_node; //insert value to the left
break;
}
else if (new_node->value < temp->value) {
temp = temp->left;
}
else if ((new_node->value > temp->value) && (temp->right == NULL)) {
temp->right = new_node; //insert value to the right
break;
}
else {
temp = temp->right;
}
}
}
} //insertNode

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