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Summary Mind map moving charges and magnetism Physics chap: Textbook For Class 12- NEET, JEE $10.49   Add to cart
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Summary Mind map moving charges and magnetism Physics chap: Textbook For Class 12- NEET, JEE

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  • NEET, JEE
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  • NEET, JEE
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  • Physics : Textbook For Class Xi

The best study meterial for moving charges and magnetism chapter in Ncert to crack competative exams like Jee, keam, neet, iiser and etc. Mind map for study. Short note

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  • Yes
  • July 2, 2023
  • 4
  • 2022/2023
  • Summary

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  • short notes
  • ncert test book
  • gravitation chapter mind map for crack neet jee
  • mind map for moving cahrges and magnetism
  • neet jee keam iiser other competative exams

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Biot-Savart Law
Formula of Field for straight wire Field Due to bent wire

dB
Idlsin θ B B2 P
r2 P
dl I B1
μ0 Idlsin θ r
dB = θ r
4π r2 )



I P
) θ/2

μ0 magnetic permiability of r β ) θ/2




)
free space or vaccum I
I
μ0= 4π+ 10-7
μ0 I [1+cos θ/2]
In vector form, Btotal=2+ 4π r
1) At point P A sinθ/2
 
 μ0 +
dB = I dl r B is into the plane
4π r3
μ0 I
   B= (sin + sin β ) I
dB is perpendicular to both dl and r using right hand 4π r
screw rule we can find direction of manetic field ) θ/2
B B1 ) θ/2 ) θ/2
2) I I
)
θ/2

Here, B is into the plane F r r
dl
/2
-θ
90


B2




)
r P
θ I
)



μ0 I [1-cos θ/2]
Btotal=2+ 4π r
Examples sinθ/2
  A
 μ I dl+ (-r) I
1) dB = 4π0 P
r3
 
-μ0 I dl+ r r P
= dl
4π r3
 
μ0 I r + dl
= Extend AB downwards and draw a perpendicular from P
4π r3
B



μ0 I (-dl)+ -r 
I
eg: Square eg: Hexagon
2) dB = r P
4π
r 
3
I
-μ0 I dl+ -r l
=
4π r3 I
 
-μ0 I r + dl dl A
=
4π r3 β
I
) )
r


μ0 I l l
 (sin - sin β )

I (-dl)+ (-r)
B=
 μ0 4π r I
3) dB = I
4π r3 P 3) Wire of infinite length
 
μ0 I dl+ r r I
= =90 and β=90 I
4π r3 l
dl l
μ0 I I
B= (sin 90 + sin 90) =900
4π r P
2 2 μ0 I 3 μ0 I
r
μ0 I β=900




MOVING
=
2π r B= B=
πl πl


4) Wire of semi infinite length

μ0 I
B=
4π r
(sin 90 + sin 0 )
Rectangle
μ
= 0I
I
I
4π r Note:-

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