Summary THE MIND MAP FOR CHAPTER GRAVITATION FOR CRACK NEET JEE KEAM EXAMS
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NEET, JEE
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NEET, JEE
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Physics : Textbook For Class Xi
The best study meterial for Gravitation chapter in Ncert to crack competative exams like Jee, keam, neet, iiser and etc.
Short note on the chapter Gravitation.
Class notes physics Physics : Textbook For Class Xi
Class notes physics Physics : Textbook For Class Xi
Mechanical properties of solids class 11th Physics ncert neet
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ROTATION OF 2 MASSES UNDER MUTUAL Variation
NEWTON‛S LAW OF VARIATION IN THE VALUE OF
GRAVITATION GRAVITATIONAL FORCE OF ATTRACTION
ACCELERATION DUE TO GRAVITY
m1 F F m2 Gm22
r V1 = Variation due to height ‘h‛
(m1+m2) r
Gm1m2 m g
v2 GM mg
F = g =
r 2
V2 =
Gm12
h (R + h)2
G - Universal gravitational constant (m1+m2) r g gR2
Value of G r1 COM r2 r g =
6.67x10-11 Nm2Kg-2 (SI or MKS) v1
r 3
(R + h)2
T2 = 4 2
6.67x10-8 dyne cm2g-2 (CGS) r G(m1+m2) Re
General Equation
Time period M Note = value
Dimensional formula [G] Approximate equation
or T2 r3 For poles
M-1L3T-2 h<<<<<<R (h < 100 km)
There is no e
2h earth on the
use, gl= g 1-
R For equator
IMPORTANT POINTS ABOUT Note the point
THREE MASSES(EQUAL) REVOLVING The effect o
GRAVITATIONAL FORCE If h<<<<R, then decrease in the value
UNDER MUTUAL GRAVITATIONAL FORCE the value of
1. Gravitational force of g with height
V M When a body
*Always attractive in nature 2hg the poles, we
GM GM Absolute decrease = g = g - gl =
R
*Independent of the nature of medium V1 = = m (gp - g
l R 3 g g-gl 2h
between masses and presence or absence of Fractional decrease = = =
l l g g R
other bodies R
g g-gl 2h x 100
2. Are central forces, acts along the centre c Time period Percentage decrease = = x 100 =
V g g R ORBITAL V
of gravity of two bodies. M
T2 l3 Orbit at a he
3. Conservative force V
l M
Variation due to depth ‘d‛ m,V
4. Force between any two masses - h
g
Gravitational force
r
d gl = g [ 1- d
] Re
Force between earth and any other body - R g
l R
M
r
Force of gravity
M Re
FOUR EQUAL MASSES UNDER MUTUAL
GRAVITATIONAL FORCE If orbit is cl
earth‛s surfa
g dg
= g-g =
l
l GM Absolute decrease = (called minimum
V = (2 2+1) g R
VECTOR FORM 2 2l Note - for e
F21 force on 2 due to 1 g g-g l
d
y
l l 1 GM Fractional decrease = = = gR = 8 km
r12 vector from m1 to m2 V = g g R
R (2 2+1)
r12
G m1m2 2 R d
m2
-r12 l Percentage decrease = g x100
GM
m1
F21 = x100 = or = 6
r2 r122 l
T2 l3 Here R = g R R
r1 2
Very imp graph
G m1m2
x or - r12 The graphical representation of change in KE, PE OR T
r123
Similarly the value of g‛ with height and depth SATELLITE
F12 force on 1 due to 2 GRAVITY gl
GMm
Acceleration due to gravity GMe KE =
G m1m2 G m1m2 2r
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